The two of the equation x ^ 2 + 2 (P + 1) x + 2p-5 = 0 are both negative numbers. The value range of the real number P is obtained

The two of the equation x ^ 2 + 2 (P + 1) x + 2p-5 = 0 are both negative numbers. The value range of the real number P is obtained

b²-4ac=4(p+1)²-4(2p-5)
=4(p²-6p+21)
=4(p-3)²+48>0
P is any real number
X1+X2=-2(P+1)<0 P>-1
X1·X2=2P-5>0 P>5/2
The total result is: P > 5 / 2