Arrange three numbers in turn: 3,9,8. For any two adjacent numbers, subtract the number on the left from the number on the right. The difference is written between the two numbers. A new number string can be generated: 3,6,9, - 1,8. This is called low order operation. Continue to operate in turn. Q: sum of all numbers after the 2009 operation Write down the process. Thank you!

Arrange three numbers in turn: 3,9,8. For any two adjacent numbers, subtract the number on the left from the number on the right. The difference is written between the two numbers. A new number string can be generated: 3,6,9, - 1,8. This is called low order operation. Continue to operate in turn. Q: sum of all numbers after the 2009 operation Write down the process. Thank you!

With A1, A2 an
After low operation, it is:
a1,（a2-a1）,a2………… （an-a（n-1））,an
After a low operation, the total is more
（a2-a1）+……… （an-a（n-1））=an-a1
In 3,9,8, A1 constant = 3, an constant = 8, so the sum of one low operation is increased by 5
After 2009, add 2009 * 5 = 10045
So the sum after 2009 is 3 + 9 + 8 + 10045 = 10065