The equation (3a-2) x & # 178; + 4ax + 2aX + 2A + 2 = 0 has two unequal real roots,

The equation (3a-2) x & # 178; + 4ax + 2aX + 2A + 2 = 0 has two unequal real roots,

(3a-2)x²+4ax+2ax+2a+2=0
(3a-2)x²+6ax+2a+2=0
According to the meaning of the title
3a-2≠0
Δ=(6a)²-4(3a-2)(2a+2)>0
36a²-4(6a²-4a+6a-4)>0
9a²-6a²-2a+4>0
3A & # 178; - 2A + 4 > 0
∴a≠2/3
That is, the value range of a is a ≠ 2 / 3