Given that the even function f (x) = loga | X-B | increases monotonically on (- ∞, 0), then the relationship between F (a + 1) and f (B + 2) is () A. f（a+1）≥f（b+2）B. f（a+1）＞f（b+2）C. f（a+1）≤f（b+2）D. f（a+1）＜f（b+2）

Given that the even function f (x) = loga | X-B | increases monotonically on (- ∞, 0), then the relationship between F (a + 1) and f (B + 2) is () A. f（a+1）≥f（b+2）B. f（a+1）＞f（b+2）C. f（a+1）≤f（b+2）D. f（a+1）＜f（b+2）

∵ y = loga | X-B | is an even function | loga | X-B | = loga | - X-B | - X-B | = | - X-B | - x2-2bx + B2 = x2 + 2bx + B2 is arranged to be 4bx = 0. Since x is not always 0, B = 0 becomes y = loga | x | when x ∈ (- ∞, 0), because the inner function is a decreasing function, and even function y = loga | X-B | is in the region