It is known that the image of quadratic function y = x2 + BX + C passes through two points a (n, - 2), B (1, m) on the line y = x-4. (1) find the value of B, C, m, N; (2) find the value of B, C, m, N; (3) find the value of B, C, m, N; (4) find the value of B, C, m, m, N; (4) find the value It is known that the image of quadratic function y = x2 + BX + C passes through two points a (n, - 2), B (1, m) on the line y = x-4 (1) Find the value of B, C, m, n; (2) Judge whether the point C (m, n) is on the image of the quadratic function and explain the reason

It is known that the image of quadratic function y = x2 + BX + C passes through two points a (n, - 2), B (1, m) on the line y = x-4. (1) find the value of B, C, m, N; (2) find the value of B, C, m, N; (3) find the value of B, C, m, N; (4) find the value of B, C, m, m, N; (4) find the value It is known that the image of quadratic function y = x2 + BX + C passes through two points a (n, - 2), B (1, m) on the line y = x-4 (1) Find the value of B, C, m, n; (2) Judge whether the point C (m, n) is on the image of the quadratic function and explain the reason

Because a (n, - 2), B (1, m) are two points on the straight line y = x-4
-2 = n - 4
m = 1 - 4 = -3
The results are: M = - 3; n = 2
Therefore, a (2, - 2); B (1, - 3)
Because the image of quadratic function y = x2 + BX + C passes through a (2, - 2); B (1, - 3), the coordinates of these two points are substituted into:
-2 = 4 + 2b + c
-3 = 1 + b + c
2b + c = -6
b + c = -4
The solution is: B = - 2; C = - 2
So, B = - 2; C = - 2; m = - 3; n = 2
Then the analytic expression of quadratic function is y = x ^ 2 - 2x - 2
The coordinate of C (m, n) is C (- 3,2)
When x = - 3, y = x ^ 2 - 2x - 2 = 9 + 6 - 2 = 13 2
So, C (m, n) is not on the graph of this quadratic function
I wish you a happy study