Given f (x) = (1ax − 1 + 12) · X3 (a > 0 and a ≠ 1); (1) find the domain of definition of function f (x); (2) discuss the parity of F (x); (3) if f (x) > 0 is constant in the domain, find the range of value of A

Given f (x) = (1ax − 1 + 12) · X3 (a > 0 and a ≠ 1); (1) find the domain of definition of function f (x); (2) discuss the parity of F (x); (3) if f (x) > 0 is constant in the domain, find the range of value of A

(1) In order to make the function meaningful, then AX-1 ≠ 0, that is, X ≠ 0, the domain of definition of function f (x) is {x | x ≠ 0}. (2) ∵ the domain of definition of function f (x) is {x | x ≠ 0}