It is known that y = f (x) is a function with a period of 2 π. When x ∈ [0, 2 π], f (x) = sinx2, then the solution set of F (x) = 12 is () A. {x|x=2kπ+π3，k∈Z}B. {x|x=2kπ+5π3，k∈Z}C. {x|x=2kπ±π3，k∈Z}D. {x|x=2kπ+（-1）kπ3，k∈Z}

It is known that y = f (x) is a function with a period of 2 π. When x ∈ [0, 2 π], f (x) = sinx2, then the solution set of F (x) = 12 is () A. {x|x=2kπ+π3，k∈Z}B. {x|x=2kπ+5π3，k∈Z}C. {x|x=2kπ±π3，k∈Z}D. {x|x=2kπ+（-1）kπ3，k∈Z}

∵ f (x) = sinx2 = 12, X ∈ [0, 2 π), ∵ x2 ∈ [0, π). ∵ x2 = π 6 or 5 π 6. ∵ x = π 3 or 5 π 3. ∵ f (x) is a periodic function with period 2 π, and the solution set of ∵ f (x) = 12 is {x | x = 2K π ± π 3, K ∈ Z}

Elden Ring Premiere

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