It is proved that 1 + sin2 θ + Cos2 θ / 1 + sin θ - Cos2 θ = Tan θ

It is proved that 1 + sin2 θ + Cos2 θ / 1 + sin θ - Cos2 θ = Tan θ

The problem should be (1 + sin2 θ + Cos2 θ) / (1 + sin2 θ - Cos2 θ) = cot θ prove: left = (1 + 2Sin θ cos θ + 2cos & sup2; θ - 1) / [1 + 2Sin θ cos θ - (1-2sin & sup2; θ)] = (2Sin θ cos θ + 2cos & sup2; θ) / (2Sin θ cos θ + 2Sin & sup2; θ) = [2cos θ (si