Extend the line AB to C so that BC = AB, and then extend Ba to d so that ad = 2Ab, then BC = () AB () AC; BD = () AB = () CD

Extend the line AB to C so that BC = AB, and then extend Ba to d so that ad = 2Ab, then BC = () AB () AC; BD = () AB = () CD

Extend the line AB to C so that BC = AB, and then extend Ba to d so that ad = 2Ab, then BC = (1) AB = (1 / 2) AC; BD = (3) AB = (3 / 4) CD