If a is a square matrix of order n and AAT = e, | a | = - 1, it is proved that | a + I | = 0, where I is the identity matrix

If a is a square matrix of order n and AAT = e, | a | = - 1, it is proved that | a + I | = 0, where I is the identity matrix

|A + I | = | a + AA ^ t | = | a | * | I + A ^ t | = | a | * | I + a | = - | a + I |, where the penultimate equal sign is because the determinant of transpose is equal to itself

Elden Ring Premiere

RELATED INFORMATIONS