Given that f (x) holds for any real number a, B, f (AB) = f (a) + F (b) (1) find the values of F (0) and f (1) F (0) = f (0) + F (0), so f (0) = 0 F (1) = f (1) + F (1), so f (1) = 0 I can't understand the solution process. Why is it equal to zero?

Given that f (x) holds for any real number a, B, f (AB) = f (a) + F (b) (1) find the values of F (0) and f (1) F (0) = f (0) + F (0), so f (0) = 0 F (1) = f (1) + F (1), so f (1) = 0 I can't understand the solution process. Why is it equal to zero?

Since the function f (x) holds f (AB) = f (a) + F (b) for "any" real numbers a and B, then we can take any value. How to take the value is actually very simple. We can make up what it asks us to do. In F (AB) = f (a) + F (b), there are AB, a and B, so if we want to find f (0), we should try our best to