Known vectors M1 = (0, x), N1 = (1,1), M2 = (x, 0), N2 = (y ^ 2,1) Let m = vector M1 + radical 2, vector N2, n = M2 - radical 2, vector N1, and m ‖ n, the locus of point P (x, y) is curve C (1) Let the line L: y = KX + 1 intersect with the curve C at two points a and B. If AB = (4 radical 2) / 3, the equation of the line l can be obtained

Known vectors M1 = (0, x), N1 = (1,1), M2 = (x, 0), N2 = (y ^ 2,1) Let m = vector M1 + radical 2, vector N2, n = M2 - radical 2, vector N1, and m ‖ n, the locus of point P (x, y) is curve C (1) Let the line L: y = KX + 1 intersect with the curve C at two points a and B. If AB = (4 radical 2) / 3, the equation of the line l can be obtained

(1) If you type the answer, I don't know when to type it. Let me give you a hint. Two vectors are parallel, so m = an (a is a set parameter). Substitute M1, N1, M2, N2, etc. into m and N to form an equation containing A. then put X and Y on both sides of the equation. Then separate a according to the equality of vector coordinates to form two equations, Then we get the relation which only contains X and y, and C is easy to determine;