Six digit 2006 can be divided by 99, and its last two digits are_____________ Process + answer

Six digit 2006 can be divided by 99, and its last two digits are_____________ Process + answer

Let the last two digits be x and y
99=9*11
If it is divisible by 11, then
(0 + 6 + y) - (2 + 0 + x) = 4 + Y-X divisible by 11
Y-X = 7 or - 4
If it is divisible by 9, then
2 + 0 + 0 + 6 + X + y = 8 + X + y can be divided by 9
X + y = 1 or 10
x=7,y=3
So the last two are 73

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