Let the arithmetic sequence {an}, A5 = - 3, S10 = - 40 (I) find the general term formula of the sequence {an}; (II) if the sequence {ABN} is an equal ratio sequence, B1 = 5, B2 = 8, find the first n terms and TN of the sequence {BN}

Let the arithmetic sequence {an}, A5 = - 3, S10 = - 40 (I) find the general term formula of the sequence {an}; (II) if the sequence {ABN} is an equal ratio sequence, B1 = 5, B2 = 8, find the first n terms and TN of the sequence {BN}

The first item of {an} {an} is A1, and the tolerance is D, a5 = -3, S10 = -40, and the 5757a5 = -3, S10 = -40, and the a5 + 4D + 4D = -310a1 + 10 × 92a1 + 10 × 92d = -40. The solution is: A1 = 5, d = -5, d = -5, d = -2, and {ABN} {{ABN}} is the equal ratio sequence, and B1 = 5, and B1 = 5, B2 = 8, q = ab2ab1 = a2ab1 = a8ab1 = a8a5 = 7-2 × 87-2 × 87-2 × 87-2 × 87-2 × 87-2 × 8-2 × 8-2 × 5 = 3, and Ab1 = a8ab1 = a8ab1 = a8ab1 = 7-7-2 × 87-2 × 87-2 × 87-2bn, 7-2bn = - 3N, BN = 7 2 + 3N2, the first n terms of {BN} and TN = B1 + B2 + +bn=7n2+12（3+32+… +3n）=7n2+12•3(1-3n)1-3=7n2+3n+1-34．