Ask f (x) = 1 + F (1 / x) * log2x to find f (2) =? Log2x is superscript

Ask f (x) = 1 + F (1 / x) * log2x to find f (2) =? Log2x is superscript

If f (x) = 1 + F (1 / x) * log2x (1), replace x with 1 / X and get f (1 / x) = 1 + F (x) * log2 (1 / x), that is, if f (1 / x) = 1-f (x) * log2x (2) x = 2, log2x = 1 (1) is f (2) = 1 + F (1 / 2) (2) is f (1 / 2) = 1-f (2) f (2) = 1