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f(x)=1+f(1/x)*log2x(1)把x換成1/x代入,得f(1/x)=1+f(x)*log2(1/x),也就是f(1/x)=1-f(x)*log2x(2)x=2時,log2x=1(1)為f(2)=1+f(1/2)(2)為f(1/2)=1-f(2)f(2)=1
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