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3^x:表示3的x次方 y=[3^x]/[(3^x)+1] y[(3^x)+1]=3^x y×(3^x)+y=3^x (3^x)-y(3^x)=y (1-y)(3^x)=y 3^x=y/(1-y) x=log(2)[(y)/(1-y)] 則反函數是:y=log(3)[(x)/(1-x)]
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