If the hollow part of a hollow copper ball with a volume of 30 cm3 and a mass of 178 G is filled with aluminum, what is the total mass of the ball filled with aluminum? (known: the density of aluminum is 2.7 × 103kg / m3, the density of copper is 8.9 × 103kg / m3)

If the hollow part of a hollow copper ball with a volume of 30 cm3 and a mass of 178 G is filled with aluminum, what is the total mass of the ball filled with aluminum? (known: the density of aluminum is 2.7 × 103kg / m3, the density of copper is 8.9 × 103kg / m3)

According to ρ = MV, the volume of copper after deformation is v = m ρ = 178g8.9g/cm3 = 20cm3; the volume of hollow in hollow copper ball is v empty = V ball-v copper = 30cm3-20cm3 = 10cm3; the volume of aluminum is v aluminum = V empty = 10cm3 when the hollow part is filled with aluminum; according to ρ = MV, the mass of aluminum after deformation is m aluminum = ρ aluminum V aluminum = 2.7g/cm3 × 10cm3 = 27g; the total mass of ball after aluminum filling is m = m copper + m aluminum = 178g + 27g = 205g; a: The total mass of the ball filled with aluminum is 205g