Given the function y = - x2 + 2x + 3, when x satisfies what condition, the function value y ≤ 0, when x satisfies x ≥ 2, then the range of function y is----

Given the function y = - x2 + 2x + 3, when x satisfies what condition, the function value y ≤ 0, when x satisfies x ≥ 2, then the range of function y is----

When x satisfies what condition, y ≤ 0?
In fact, it is to solve the inequality - x2 + 2x + 3 ≤ 0
When x satisfies x ≥ 2, then the range of function y is --?
Y = - x2 + 2x + 3 is a quadratic function with an opening downward, and the axis of symmetry x = 1, so when x satisfies x ≥ 2... Obviously x = 2 is the maximum point