As shown in the figure, the amphibious infantry combat vehicle has a mass of 22T and a total track landing area of 4m2. (g = 10N / kg, ρ water = 1.0 × 103kg / m3) (1) what is the pressure of the vehicle on the horizontal ground? (regardless of the mass of the person on the tank) (2) the tank has the function of hitting the target and transporting on the water. In a water drill, the volume of water discharged by the tank is 23 m3. What is the buoyancy of the tank? (3) In this water exercise, the pressure of water on the chariot is 1.5 × 104pa. What is the depth of this place?

As shown in the figure, the amphibious infantry combat vehicle has a mass of 22T and a total track landing area of 4m2. (g = 10N / kg, ρ water = 1.0 × 103kg / m3) (1) what is the pressure of the vehicle on the horizontal ground? (regardless of the mass of the person on the tank) (2) the tank has the function of hitting the target and transporting on the water. In a water drill, the volume of water discharged by the tank is 23 m3. What is the buoyancy of the tank? (3) In this water exercise, the pressure of water on the chariot is 1.5 × 104pa. What is the depth of this place?

(1) 2 × 105N / kg, P = FS = 2.2 × 105n4m2 = 5.5 × 104pa (2) the buoyancy of the vehicle by water: F = ρ water V row g = 1 × 103kg / m3 × 23m3 × 10N / kg = 2.3