In the triangle ABC, ab = C, AC = B, acute angle a = Alpha, problem (1) the length of BC

In the triangle ABC, ab = C, AC = B, acute angle a = Alpha, problem (1) the length of BC

In ACD, sin alpha = CD / AC = CD / B, then CD = sin alpha * bcos alpha = ad / AC = ad / B, then ad = cos alpha * B, so DB = ab - ad = C - cos alpha * B in ACD