If 5 (x + 2) = 2A + 3 and (3a + 1) a / 5 = (5x-3) a / 5 are the same solution equations about X, then a =? I'm sorry, I wrote it wrong. It should be 5 (x + 2) = 2A + 3 and (3a + 1) x / 3 = (5x-3) a / 5. If a =?

If 5 (x + 2) = 2A + 3 and (3a + 1) a / 5 = (5x-3) a / 5 are the same solution equations about X, then a =? I'm sorry, I wrote it wrong. It should be 5 (x + 2) = 2A + 3 and (3a + 1) x / 3 = (5x-3) a / 5. If a =?

5 (x + 2) = 2A + 3 5x + 10 = 2A + 3 5x = 2a-7 (3a + 1) x / 3 = (5x-3) a / 5 5 (3a + 1) / 3A = (5x-3) / x 5 + 5 / 3A = 5-3 / x 3 / x = - 5 / (3a) x = - 9A / 5 5x = - 9a, so 2a-7 = - 9a11a = 7a = 7 / 11 (2a-7) (3a-2) = - 9 6A ^ 2-25a + 23 = 0 a = (25 ± √ 73) / 12