If a < 0 and ab < 0 are known, then | A-B | - | ab-2 | =?

If a < 0 and ab < 0 are known, then | A-B | - | ab-2 | =?

Because A0
=> |a-b|=-(a-b)=b-a
=> |ab-2|=-(ab-2)=2-ab
So | A-B | - | ab-2 | = (B-A) - (2-AB) = b-a-2 + ab

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