Given the quadratic function f (x) = ax & # 178; + BX + C, if a > b > C and f (1) = 0, it is proved that the image of F (x) and X axis have two different intersections

Given the quadratic function f (x) = ax & # 178; + BX + C, if a > b > C and f (1) = 0, it is proved that the image of F (x) and X axis have two different intersections

From F (1) = 0, there is a + B + C = 0
And because a > b > C, so a > 0, C