There are two cylinders with the same diameter at the bottom. The height ratio of the two cylinders is 7:4. The volume of the second cylinder is 24 cubic decimeters less than that of the first cylinder How much is it
Let R be the bottom radius and H be the height, so v2-v1 = π R2 * 3H = 24 π R2 * H = 8
And V1 = π R2 * 7h = 7 * 8 = 56
So the volume of the first cylinder is 56 cubic decimeters