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3x^3-21x+18=0 ∴ 3x³-3x-18x+18=0 That is, 3x (X & # 178; - 1) - 18 (x-1) = 0 ∴ 3x(x+1)(x-1)-18(x-1)=0 ∴ x(x+1)(x-1)-6(x-1)=0 ∴ (x-1)*[x(x+1)-6]=0 ∴ (x-1)(x²+x-6)=0 ∴ (x-1)(x-2)(x+3)=0 Ψ x = 1 or x = 2 or x = - 3
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