Motor, u = 110V, r = 0.4 ohm, normal operation, I = 0.5A, find 1. Work done by current per second, heat generated per second, Q

Motor, u = 110V, r = 0.4 ohm, normal operation, I = 0.5A, find 1. Work done by current per second, heat generated per second, Q

W = uit = 110V × 0.5A × 1s = 55jq = i2rt = (0.5A) 2 × 0.4 ohm × 1s = 0.1j the work done by the current through the motor is mainly converted into mechanical energy, a small part of which is converted into heat energy (internal energy) due to the resistance of the motor coil

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