There is a road beside the railway parallel to the railway. A 160 meter long train runs eastward at the speed of 54 kilometers per hour. At 7:10 a.m., it meets a worker walking westward and leaves the worker 10 seconds later. At 7:20 a.m., it meets a motorcycle running westward. After 5 seconds, it leaves the motorcycle and asks when it will catch up with the worker?

There is a road beside the railway parallel to the railway. A 160 meter long train runs eastward at the speed of 54 kilometers per hour. At 7:10 a.m., it meets a worker walking westward and leaves the worker 10 seconds later. At 7:20 a.m., it meets a motorcycle running westward. After 5 seconds, it leaves the motorcycle and asks when it will catch up with the worker?

Train speed: 54000 △ 3600 = 15 (M / s), workers' speed: 160 △ 10-15, = 16-15, = 1 (M / s), motorcyclists' speed: 160 △ 5-15, = 32-15, = 17 (M / s), the distance of the train from 7:10 to 7:20: 7:20-7:10 = 10 (min) = 600 seconds, 15 × 600 = 9000 (m), the distance of workers at 7:20: 1 × 600 = 600 (m), workers and workers The distance between trains is: 9000 + 600 = 9600 (m). The time for motorcyclists to catch up with workers is: 9600 △ 17-1, = 9600 △ 16, = 600 (s), = 10 minutes. 7:20 + 10 minutes = 7:30. A: motorcycles will catch up with workers at 7:30