How to convert ppm, mg / L and Mg / m3? What are the conversion relations among their three units? Brother, I don't want to copy it. I can find it too!

How to convert ppm, mg / L and Mg / m3? What are the conversion relations among their three units? Brother, I don't want to copy it. I can find it too!


Ppm is the unit of concentration. For water, the density is 1g / cm & sup3;
Therefore, 1ppm = 1mg / kg = 1mg / L = 1 × 10-6
1mg/L=1000mg/m³
1ppm=1000mg/m³



What's the relationship between ppm, mg / L, mg / DM, mg / kg, and how to convert it, such as 1ppm, what's the other unit?


1 ppm is 1 ppm. Mg / L is mg / L. mg / DM2 is mg / square decimeter. Mg / kg is mg / kg (kg). If necessary, the discussion can be continued



How to convert the relationship between PG, ng, UG and Mg and the relationship between L, ML and DL?


As far as I know, Mg, μ g, ng and PG represent mg, μ g, ng and PG respectively, and their relationship is 1000 times, that is, 1 mg = 1 000 μ g, 1 μ g = 1 000 ng and 1 ng = 1 000 pg. similarly, l, ML and DL represent L, ML and DL respectively, and their relationship is: 1L = 10 DL = 1 000 ml (1 L = 1 cubic decimeter)
I don't know if the symbols you listed are different



How many moles of electrons are there in 0.1mol oxygen
Chemistry practice in senior one


One o has eight electrons
One oxygen has 16
So it's 1.6mol



Calculation formula for gas flow rate of 1.6Mpa steam pipeline?
How to convert? How to calculate the gas flow rate


The specific volume of saturated steam at 1.6Mpa (gauge pressure) is 0.1189 (m3 / kg); the specific weight of saturated steam is 8.410 (kg / m3). (the property of superheated steam is related to temperature, so it can only be calculated with saturated steam.)
The average velocity in the steam pipe is about 25m / s. The volume flow in the pipe is equal to the velocity multiplied by the cross-sectional area of the pipe. With the above two parameters, the weight flow can be easily obtained



How many tons of cement, sand and stone are needed to make 96 tons of concrete with cement, sand and stone in the ratio of 2:3:5?


96 × 22 + 3 + 5 = 19.2 (tons); 96 × 32 + 3 + 5 = 28.8 (tons); 96-19.2-28.8 = 48 (tons); a: 19.2 tons of cement, 28.2 tons of sand and 48 tons of stone are required



It is known that in the same state, the number ratio of molecules between gas molecules is equal to the volume ratio of gas molecules. The volume of the existing 9ml Co, O2 and CO2 mixture is reduced by 1ml when it returns to the original state after ignition and explosion, and by 5ml when it passes through sodium hydroxide solution, then the volume ratio of CO, O2 and CO2 in the original mixture is reduced by 1 ml?


Let the volume of carbon monoxide and oxygen in the reaction be x, y, and the volume of carbon dioxide produced be Z, then: 2CO + O2 & nbsp; ignites & nbsp;. & nbsp; 2co22 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 1 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; volume decreases by 1 x & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; Y & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; When the volume is reduced by 1ml, the solution is x = 2ml according to 21 = x1ml; y = 1ml according to 11 = y1ml; Z = 2ml according to 21 = z1ml; therefore, the volume of carbon monoxide participating in the reaction is 2ml; the volume of oxygen is 1ml; the volume of carbon dioxide generated is 2ml; and because the volume is reduced by 5ml after passing through sodium hydroxide solution, the volume of carbon dioxide is 5ml, so the original volume of carbon dioxide is 5ml-2ml = 3ml The volume of residual gas is 9ml-1ml-5ml = 3ml; assuming that the residual gas is carbon monoxide, the volume of carbon monoxide is 2ml + 3ml = 5ml, so the volume ratio of CO, O2 and CO2 is 5ml: 1ml: 3ml = 5:1:3; assuming that the residual gas is oxygen, the volume ratio of oxygen is 1ml + 3ml = 4ml, so the volume ratio of CO, O2 and CO2 is 2ml: 4ml: 3ml = 2:4:3; so the answer is 5:1:3 or 2:4:3



How to calculate pipeline pressure loss


In fact, it is to calculate the total loss of pipeline resistance
The pipeline is divided into local resistance and along the way resistance: 1. The local resistance is formed by the pipeline accessories (elbow, tee, valve, etc.), which is proportional to the local resistance coefficient and dynamic pressure. The local resistance coefficient can be obtained by referring to the manual according to the type and opening of accessories, and the dynamic pressure is proportional to the square of the flow velocity. 2. The along the way resistance is the specific friction multiplied by the pipeline length, and the specific friction is determined by the pipe diameter and the roughness of the inner wall, Determination of fluid velocity
In a word, the magnitude of pipeline resistance is related to the average velocity of fluid, viscosity of fluid, size of pipeline, length of pipeline, gas and liquid of fluid, smoothness of inner wall of pipeline. Its calculation is complex, classification is various, and error is large. If you want to understand it, you should learn "fluid mechanics". If it is difficult to understand it, you can also use "chemical process calculation manual" written by Liu Guangqi



How many tons of cement, sand and stone are needed to make 96 tons of concrete with cement, sand and stone in the ratio of 2:3:5?


96 × 22 + 3 + 5 = 19.2 (tons); 96 × 32 + 3 + 5 = 28.8 (tons); 96-19.2-28.8 = 48 (tons); a: 19.2 tons of cement, 28.2 tons of sand and 48 tons of stone are required



It is known that in the same state, the number ratio of molecules between gas molecules is equal to the volume ratio of gas molecules. The volume of the existing 9ml Co, O2 and CO2 mixture is reduced by 1ml when it returns to the original state after ignition and explosion, and by 5ml when it passes through sodium hydroxide solution, then the volume ratio of CO, O2 and CO2 in the original mixture is reduced by 1 ml?


Let the volume of carbon monoxide and oxygen in the reaction be x, y, and the volume of carbon dioxide produced be Z, then: 2CO + O2 & nbsp; ignites & nbsp;. & nbsp; 2co22 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 1 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; volume decreases by 1 x & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; Y & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; When the volume is reduced by 1ml, the solution is x = 2ml according to 21 = x1ml; y = 1ml according to 11 = y1ml; Z = 2ml according to 21 = z1ml; therefore, the volume of carbon monoxide participating in the reaction is 2ml; the volume of oxygen is 1ml; the volume of carbon dioxide generated is 2ml; and because the volume is reduced by 5ml after passing through sodium hydroxide solution, the volume of carbon dioxide is 5ml, so the original volume of carbon dioxide is 5ml-2ml = 3ml The volume of residual gas is 9ml-1ml-5ml = 3ml; assuming that the residual gas is carbon monoxide, the volume of carbon monoxide is 2ml + 3ml = 5ml, so the volume ratio of CO, O2 and CO2 is 5ml: 1ml: 3ml = 5:1:3; assuming that the residual gas is oxygen, the volume ratio of oxygen is 1ml + 3ml = 4ml, so the volume ratio of CO, O2 and CO2 is 2ml: 4ml: 3ml = 2:4:3; so the answer is 5:1:3 or 2:4:3