5 out of 12 times 1 out of 7 plus 7 out of 12 times 1 out of 7 Simple calculation!

5 out of 12 times 1 out of 7 plus 7 out of 12 times 1 out of 7 Simple calculation!

5 out of 12 times 1 out of 7 plus 7 out of 12 times 1 out of 7
=(5 out of 12 plus 7 out of 12) times 1 out of 7
=One by one in seven
=One in seven

If the intersection point between positive scale function and inverse scale function is required, how to find it?
Here's a question
Y = - 2x y = - 1 / X to find the intersection point
It's better to tell me how to ask for it in general,

It's very simple, isn't the intersection satisfying two functional relations? Let's say y = - 2x = - 1 / 2 of X, X is not equal to 0, so multiply both sides by X to get 2x ^ 2 = 1, x ^ 2 = 1 / 2. So x = positive and negative root 2 / 2
Substituting x = positive and negative root 2 / 2 into any formula, y = positive and negative root 2. So p (x, y) is
(+ root 2 / 2, - root 2) (- root 2 / 2, + root 2) understand?

How much is a quarter multiplied by minus eight multiplied by a third

Minus two thirds

If a set a = {1, 2, 3}, B = {1, 3, 4}, then the number of subsets of a ∩ B is ()
A. 2B. 3C. 4D. 16

If ∩ a = {1, 2, 3}, B = {1, 3, 4}, ∩ a ∩ B = {1, 3}, then the number of subsets of a ∩ B is 22 = 4

100 fish 100 Jin, 1 big fish 10 jin, 1 middle fish 1 jin, 1 big fish 1 Liang (1 jin = 16 Liang)

According to the question meaning: 160 taels of big fish, 16 taels of middle fish, 1 taels of small fish. Suppose there are x taels of big fish, y taels of middle fish, Z taels of small fish. We get the equation, 160x + 16y + Z = 1600 (the weight of all the fish is 1600 taels, so the weight of all the big fish plus the weight of all the middle fish plus the weight of all the small rain is the total weight) x + y + Z = 1

Why is the sum of three ones equal to 7
Yes, it's a brain twister

1+1+1
A total of seven

7 (4-x) = 9 (x-3) equation,

28-7x=9x-27
-16x=-58
x=29/8

Solution equation: (cosx) ^ n - (SiNx) ^ n = 1 (n ∈ positive integer)

(1) When n is an even number, the original formula can be reduced to (COS & sup2; X + Sin & sup2; x) [(cosx) ^ (n-2) - (SiNx) ^ (n-2)] = 1 and COS & sup2; X + Sin & sup2; X = 1, so the number of unknowns of the original equation is reduced from n to n-2. Similarly, it is reduced to Cos & sup2; x-sin & sup2

X divided by 60-5 = x divided by 75 + 2

X divided by 60-5 = x divided by 75 + 2
X divided by 60 - (5 + 2) = x divided by 75
60 X-7 = 75 x
60 x-75 x = 7
5x of 300-4x of 300 = 7
X of 300 = 7
X = 7 times 300
x=2100

Quadratic application of one variable
The perimeter of a diamond is 40, and the difference between two diagonals is 4
One yuan twice. No two yuan

12,16
Let the length of one diagonal be 2x, then the other is 2x + 4
Because the diagonals of the diamond are vertical and the four sides are equal,
Then the length of the side is 10 and there are two sides
x^2+(x+2)^2=10^2
One is 12 and the other is 16