4 () 3 divided by 5, () 62 divided by 9, so that the end of the quotient has 0

4 () 3 divided by 5, () 62 divided by 9, so that the end of the quotient has 0

These two numbers are 403 362. The end of quotient is 0, but there is remainder

All the formulas of circle, cylinder and cone, note that they are all
It's better to have all the formulas of circle, cylinder and cone with numbers and full points,

Volume: bottom area × height surface area: sum of side area + sum of bottom area × 2 volume formula of cone: bottom area × height × one third cylinder side area: bottom perimeter x height surface area of cylinder is: bottom perimeter

Calculation: 80 ° 32 ′ 15 ″ + 90 ° 27 ′ 45 ″=______ ；100°-36°18′52″=______ ．

80°32′15″+90°27′45″=171°；100°-36°18′52″=63°41′8″．

Find the unknown x.3.2 × 2.5-75% x = 212 ÷ (0.5x + 1) = 4 (x-1): 37 = 0.1:374x-24 = 2x + 20

（1）3.2×2.5-75%x=2               8-0.75x=2         8-0.75x+0.75x=2+0.75x                   8-2=2+0.75x-2                6÷0.75=0.75x÷0.75                     x=8（2）12÷（0.5x+1）=412÷（0.5x+1）×（0.5x+1）=4×（0.5x+1）                     12÷4=4×（0.5x+1）÷4                 0.5x+1-1=3-1                0.5x÷0.5=2÷0.5                         x=4（3）（x-1）：37=0.1：37            x-1=0.1          x-1+1=0.1+1              x=1.1（4）4x-24=2x+204x-24-2x+24=2x+20-2x+24         2x=44      2x÷2=44÷2          x=22

1. Six eleven times seven fifteen times ten 2. Nineteen one hundred times three eight times fifty
reply promptly

1.6/11*7/15*10=28/11；
　　2.19/100*3/8*50=57/16.

3x + 2Y + 2Z = 302,5x + 3Y + 3Z = 508 find the value of X + y + Z
fast

3X+2Y+2Z=302
6X+4Y+4Z=604
X+Y+Z=96

How much is eight times eight? How much is nine times nine?

8×8=64 9×9=81

As shown in the figure, AB is the diameter of the semicircle o, AE is a chord of ⊙ o, and C is the midpoint of. If AE = a, CD ⊥ AB is the length of CD at D
As shown in the figure, AB is the diameter of semicircle o, AE is a chord of ⊙ o, C is the midpoint of arc AE, if AE = a, CD ⊥ AB is in D
Find the length of CD. (many methods)

Extend CD, intersect circle O at point F
∵DF⊥AB
Ψ arc AF = arc AC
∵ C is the midpoint of arc AE
‖ arc AC = arc CE
Ψ arc AE = arc CF
∴AE=CF
∴CD=1/2CF=1/2AE=a/2

In the calculation, Xiao Gang took the divisor 72 volume as 27, the result is 58, the remainder is 18, what is the correct quotient?

1. This is a question of "seeking the right from the wrong"
2. The idea of your problem is to find the right divisor according to the wrong divisor, wrong quotient and remainder
3. Correct divisor: 27 × 58 + 18 = 1584
4. Correct quotient: 1584 △ 72 = 22

As shown in the figure, ABC is an equilateral triangle, BD is the middle line, extend BC to e, so that CE = CD

It is proved that: ∵ ABC is an equilateral triangle, BD is the middle line, ∵ ABC = ∠ ACB = 60 °, DBC = 30 ° (isosceles triangle three lines in one), and ∵ CE = CD, ∵ CDE = ∠ CED. And ∵ BCD = ∠ CDE + ∠ CED, ∵ CDE = ∠ CED = 12 ∠ BCD = 30 °. ∵ DBC = ∠ Dec. ∵ DB = de (equiangular to equilateral)