Centimeter scale conversion I don't need to say much nonsense. I measured the waist circumference of 88cm and changed it into the size to give it an authoritative point, because I saw some people saying that 1m = 3ft and others saying that 1ft = 30.48cm. I don't know who is right,

Centimeter scale conversion I don't need to say much nonsense. I measured the waist circumference of 88cm and changed it into the size to give it an authoritative point, because I saw some people saying that 1m = 3ft and others saying that 1ft = 30.48cm. I don't know who is right,

We usually say one foot is 33cm, 88cm is about 2.64ft. You say waist circumference is to buy clothes. If you buy clothes, you should change it into inches. 88cm is about 34.5inches

Square meter for centimeter
How many centimeters is 12.6 square meters?
How is that?
Wrong. It's 12.6 square centimeters for centimeters

It can't be changed
Square centimeter and centimeter are not the same unit

There are 124 students in the sixth grade of a school. Three eighth of the boys are equal to two fifth of the girls. How many boys and girls are there in the sixth grade?

Suppose the number of boys is a and that of girls is (124-A)
According to the Title A * 3 / 8 = (124 - a) * 2 / 5
15 * a = 16 * ( 124 -a)
Male: a = 64
Female: 124 - 64 = 60

It is known that when x = - 2, the value of the algebraic formula AX3 + BX + 1 is 6, then when x = 2, the value of the algebraic formula AX3 + BX + 1 is ()
A. 6B. -6C. 4D. -4

When x = - 2, the algebraic formula is - 8a-2b + 1 = 6, that is, 8A + 2B = - 5, then when x = 2, the algebraic formula is 8A + 2B + 1 = - 5 + 1 = - 4

There are 16 more boys than 25 girls in class 6 (1), and 12 more girls than boys. How many boys are there in class 6 (1)?

A: there are 20 boys in class 6 (1)

Factorization of the square of (x + y) - (x + y) - 56

﹙x+y)²-﹙x+y)-56=(x+y+7)(x+y-8)
Multiplication x + y + 7 by cross phase
x+y -8

There are three schools: school a, School B and school C. 12% of the number of school a is equal to 13% of the number of School B and 37% of the number of school C. It is known that school C has 120 more students than school A. how many students are there in the three schools?

The number of students in school a: 120 △ 37-1, = 120 △ 76-1, = 120 △ 16, = 720; the number of students in school B: 720 × (12 △ 13), = 720 × 32, = 1080; the number of students in school C: 720 + 120 = 840; the number of students in three schools: 720 + 840 + 1080 = 2640

If the position of rational number on the number axis is as shown in the figure --- C -- B -------- 0 --- a --
Try to simplify: a + C + a-b - C + B=

According to the figure: C < B < 0 < A;
∴a+c＜0；a-b＞0；b+c＜0；
The original formula = - a-c + a-b - (- B-C)
=-b-c+b+c
=0;
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The average number of a, B and C is 50. Their ratio is 6:5:4. What's a, B and C

Sum of three numbers = 50 × 3 = 150
A = 150 × 6 / (6 + 5 + 4) = 60
B = 150 × 5 / (6 + 5 + 4) = 50
C = 150 × 4 / (6 + 5 + 4) = 40

How to prove: let a and B be positive real numbers, and the absolute value of (a ^ 3-B ^ 3) is 1, then the absolute value of (a-b) is less than 1

1=|a^3-b^3|=|(a-b)(a^2-ab+b^2)|>|(a-b)(a^2-2ab+b^2)|=|(a-b)^3|
That is: | (a-b) ^ 3|