The length is a meter, the area s of the rectangle, and the width

s/a

(1) The area of a rectangle is 0.64 square meters. What are its length and width?

Let the rectangle be x in length and Y in width
XY=0.64
X=0.64/Y
You can just pick a number and bring in X, and then y comes out

The area of a rectangle is 0.64 square meters. What are its length and width?
There should be a formula

This is a lot, as long as the multiplication of two numbers is 0.64
Such as 0.1 and 6.4; 0.2 and 3.2; 0.4 and 1.6; 0.8 and 0.8; etc

In an arithmetic sequence with even terms, which formula can be used to express the sum of odd and even terms

Sum of odd items:
Sn=[2a1+(n-2)d]n/4
Sum of even terms:
Sn=[a1+d+a1+(n-1)d]n/4
=(2a1+nd)n/4

Simple calculation 1 + 2 + 3 + 4 + 5 What is + 49 + 50

　　1+2+3+4+5+…… +49+50
Add 1 and 50, 2 and 49, 3 and 48 By analogy, there are 25 groups
　　（1+50）+（2+49）+（3+48）+…… +（25+26）
Because addition has commutative law and associative law, it does not affect the result
It is found that the sum in each bracket is 51, a total of 25 groups
　　51×25
　　=1275

(5 / 24-4 / 25) * 25 * 24

(5 / 24-4 / 25) * 25 * 24
=5/24*24*25-4/25*25*24
=125-96
=29

Sum: SN = 2 ^ / 1 * 3 + 4 ^ 2 / 3 * 5 + (2n)^2/(2n-1)(2n+1)

(2n)^2/(2n-1)(2n+1)=(2n)^2/[(2n)²-1]=1+1/[(2n)²-1]=1+1/(2n-1)(2n+1)=1+1/2[1/(2n-1)-1/(2n+1)]∴Sn=2^2/1*3+4^2/3*5+…… (2n)^2/(2n-1)(2n+1)=n+1/2[1-1/3+1/3-1/5+...+1/(2n-1)-1/(2n+1)]=n+1/2[1-1/...

Given that the function f (x) = ax + 1 / x + 2 is an increasing function in the interval (- 2, positive infinity), find the value range of A

f(x)=(ax+2a-2a+1)/(x+2)
=a(x+2)/(x+2)+(-2a+1)/(x+2)
=a+(-2a+1)/(x+2)
When x > 0 is an increasing function, the coefficient is less than 0
So here's - 2A + 11 / 2

The greatest common divisor and the least common multiple of 48 and 120

24 240

If a > 0, b > 0, ab ≥ 1 + A + B, then the minimum value of a + B is______

Therefore, the answer is 2 + 22

The length is a meter, the area s of the rectangle, and the width