The bottom of a triangle is 3 decimeters, and its area is square decimeters. How many decimeters is its height

The bottom of a triangle is 3 decimeters, and its area is square decimeters. How many decimeters is its height

Let the area be s and the height be X
S=3×X÷2
S=1.5X
X=1.5/S
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Lie equation: (5.3 + 2.7) x divided by 2 = 60

8x=120
x=15

A circle with a radius of 3 decimeters, if the radius is increased by 1 decimeter, then the circumference is increased______ Decimeter, area increased______ Square decimeter

Later, the radius of the circle: 3 + 1 = 4 (decimeter), perimeter increase: 2 × 3.14 × 4-2 × 3.14 × 3, = 6.28 × 4-6.28 × 3, = 25.12-18.84, = 6.28 (decimeter); area increase: 3.14 × 42-3.14 × 32, = 50.24-28.26, = 21.98 (square decimeter); answer: perimeter increase: 6.28 decimeter, area increase: 21.98 square decimeter; so the answer is: 6.28, 21.98

I forgot to simplify the format
Right?
4x+6x
=10x
There's another one
How to simplify 2A + 2B?

2(a+b)

Known: as shown in the figure, △ ABC is an isosceles right triangle with a point O inside, connecting OA, ob, OC, OA = 2, OB = 3, OC = 1, find the degree of ∠ AOC

135°

The condition of Holder Inequality equal sign
Is it similar to Cauchy inequality?

The holder inequality is known as AI, Bi , Li () is a positive real number, and α, β , λ is a positive number, and α + β + +If λ = 1, then ∑ (AI) ^ α (BI) ^ β (li)λ≤(∑ai)^α (∑bi)^β …… (∑li)^λ,i=1,2,…… If AK / ∑ AI = BK / ∑ bi

As shown in the figure below, the area of triangle ABO is 9 square centimeters, the length of line Bo is 3 times of OD, and the area of trapezoid ABCD is how many square centimeters?

Triangle area = 1 / 2 * bottom * high bottom, Bo = 3Do → s △ ABO = 3S △ ADO = 9, s △ cod = 3S △ AOD = 9
If the trapezoidal upper bottom is parallel to the lower bottom, then ad ‖ BC → AO / CO = Bo / AO = 3, CO = 3AO
→S△BOC=3S△DOC=2*9=27
S trapezoid ABCD = sum of area of four triangles = 3 + 9 + 9 + 27 = 48

What is LG1 LG2 Lg3 LG4. Lg9
I mean LG2 = Lg3 = LG4 =.... lg9 = thank you very much

lg1=0
lg2=0.3010
lg3=0.4771
lg4=0.6021
lg5=0.6990
lg6=0.7782
lg7=0.8451
lg8=0.9031
lg9=0.9542

The circumference of the cone's bottom surface is 12.56 decimeters, and its height is 3 decimeters. How many square decimeters is its bottom area, and how many cubic decimeters is its volume?

R = 12.56 / 3.14 / 2 = 2 (decimeter)
S bottom = 2 * 2 * 3.14
=4*3.14
=12.56 (square decimeter)
V=Sh
=12.56*3
=37.68 (cubic decimeter)

Find the maximum value of function y = (4a ^ 2 + x ^ 2) ^ (1 / 2) + ((x-a) ^ 2 + A ^ 2) ^ (1 / 2) (a > 0)
Let Z1 = x + 2ai, Z2 = A-X + AI

In this paper, we want to make the Z1 = x + 2ai Z2 = A-X + AI, so the Z1 + Z2 = a + 3aiz1-z2 = a + 3aiz1-z2 = - A + 3aiz1-z2 = - A + A + A, then y = 124\124124124124\124\\124\\\\\124\124\\\\\\124\\124\\\\\\\no. 10; y has no maximum value