Given the absolute value of X + 3 = - (2x + y) & sup2;, find the value of 3x & sup2; - 3Y + 4x & sup2; + y Given the absolute value of X + 3 = - (2x + y) & amp; sup2;, find the value of 3x & amp; sup2; - 3Y + 4x & amp; sup2; + y

Given the absolute value of X + 3 = - (2x + y) & sup2;, find the value of 3x & sup2; - 3Y + 4x & sup2; + y Given the absolute value of X + 3 = - (2x + y) & amp; sup2;, find the value of 3x & amp; sup2; - 3Y + 4x & amp; sup2; + y

Because the absolute value of X + 3 is greater than or equal to 0, - (2x + y) &# 178; less than or equal to 0
So x + 3 = 0, and 2x + y = 0
So x = - 3, y = 6
Put x = - 3, y = 6 into the fraction

Function f (x) {(x ^ 2 + 5x) / 6,0 ≤ x

F (x) increases on (0,3), decreases on (3,5), and decreases on (3,5)
f(0)=0,f(3)=4,f(5)=0
（1）m

The image of inverse scale function y = − 2m − 1x (M is a constant) is shown in the figure, then the value range of M is______ ．

Therefore, the answer is: m ＜ - 12

If the sum of each digit of a number is equal to 12, the number of its individual digit is 2 less than the number of its ten digit. If its hundred digit and individual digit are interchanged, the number ratio is obtained
(Continued) the original number is smaller than 99, find the original number (write process)

Let ten digits be x, then the single digit is X-2, the hundred digit is 12 - (x + X-2) = 14-2x, the original number is 100 (14-2x) + 10x + X-2 = 1398-189x, the later number is 100 (X-2) + 10x + 14-2x = 108x-1861398-189x-108x + 186 = 99297x = 1485x = 5, so the ten digits are 5, the three hundred digits are 4, and the original number is 453

If 3A + 2B = 10, find the value of the algebraic formula 18a square + 24ab + 8b square + 1

From 18a & sup2; + 24ab + 8b & sup2; + 1
=（3a+2b）（6a+4b）+1
=2（3a+2b）²+1
=2×10²+1
=201.

Solve equation 4.5x-1.52 = 5

4.5x-1.52=5
4.5x=6.52
x=326/225

Given the ellipse x ^ 2 / 9 + y ^ 2 / 4 = 1 and point d (2,1), through point D, any straight line intersection ellipse is drawn at two points a and B, and the trajectory equation of midpoint m of line AB is obtained
The answer to this is 4x + 9y - 8x-9y = 0

The crux of this problem is not whether it can be done, but whether it can be calculated-
Let a (x1, Y1); B (X2, Y2); m (x0, Y0)
Let the line AB: Y-1 = K (X-2) be substituted into the ellipse 4x ^ 2 + 9y ^ 2 = 36
4x^2+9[ kx-(2k-1)]^2=36→ (4+9k^2)x^2 - 18(2k-1)kx+9(2k-1)^2-36=0
So x0 = (x1 + x2) / 2 = 9 (2k-1) K / (4 + 9K ^ 2) substitute (y0-1) / (x0-2) = K into
x0 = 9(y0-1)(2y0-x0)/[4(x0-2)^2+9(y0-1)^2]
4x0(x0-2)^2+9x0(y0-1)^2 -9(y0-1)(2y0-x0) = 0
→4x0(x0-2)^2+9(y0-1)[ x0y0-x0-2y0+x0]=0
→4x0(x0-2)^2+9(y0-1)y0(x0-2)=0
→ 4x0(x0-2) + 9 (y0-1)y0=0
The trajectory equation is 4x ^ 2-8x + 9y ^ 2-9 = 0

When two BCD codes (01111000) and (01101001) are added, the result is equal to?

Dear landlord
6=0110 7=0111 8=1000 9=1001
I wish you a happy New Year!
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Let a and B be nonzero real numbers, then the set of ownership of x = A / LAL + LBL / B + labl / AB is_____ .
Please, I haven't learned it. Come on!

If both a and B are greater than 0
Then x = 1 + 1 + 1 = 3
If a and B are positive and negative
Then x = - 1 + 1-1 = - 1
If a and B are both smaller than 0
Then x = - 1-1 + 1 = - 1
So the set is {3, - 1}

What is the range of function f (x) = 5x ^ 2-6x + 2 on (0,1]?

Solution f (x) = 5x ^ 2-6x + 2
=5 (x-3 / 5) ^ 2 + 1 / 5 x belongs to (0,1]
We know that when x = 3 / 5, y has a minimum value of 1 / 5
When x = 0, y has a maximum of 2
So the range of the function is [1 / 5,2]