Factorization: (y + 2) x ˇ 2 + (y + 2) x-12y-24

:(y+2)xˇ2+(y+2)x-12y-24
=(y+2)x²+(y+2x)-12(y+2)
=(y+2)(x²+x-12)
=(y+2)(x+4)(x-3)

Connect a 5-ohm resistor in series with a 10 ohm resistor into the circuit. If the current through the 5-ohm resistor is 1 A, then the current through the 10 ohm resistor must be ()
A. 2 a B. 1.5 A C. 1 a D. 0.5 A

It can be seen from the title that two resistors are connected in series, and the current passing through a 5 ohm resistor is 1a, ∵ the current in each part of the series circuit is equal, ∵ the current passing through a 10 ohm resistor is equal to the current passing through a 5 ohm resistor, which must be 1A

What is the answer to 2x4x6... X100? If there is a formula, please tell me the formula,

Use the following formula for calculation
=POWER(2,50)*FACT(50)
＝3.4243224702512E+79

In the circuit as shown in the figure, the resistance R1 = 8ohm, R2 = 10ohm, the supply voltage and the resistance of the constant resistance R are unknown. When the switch S is connected to position 1, the current indication is 0.2A. When the switch S is connected to position 2, what range is the indication of the ammeter? The answer is 0.16 to 0.2
But the power supply voltage does not change, no matter how much R is in the circuit! When connected to 2, the total resistance must be larger. According to Ohm's law, the total current must be smaller than the original. How can it be 0.2A!

It's smaller than 0.2A, but how do you express it? Because you are in junior high school, you use the range of 0.16A ~ 0.2A to express it. In fact, strictly speaking, neither 0.16A nor 0.2A can be taken (that is, you say it's bigger than 0.2A, in fact it's bigger than 0.16A). In senior high school, you use the interval to express it (0.16,0.2), which means it's greater than 0.16 but less than 0.2, while [0.16,0.2] means it's greater than or equal to 0.16 but less than 0.2,0.16, [0.16,0.2] means greater than or equal to 0.16 but less than or equal to 0.2, 0.2 is accessible, and [0.16,0.2] means greater than or equal to 0.16 but less than or equal to 0.2, 0.16,0.2 are accessible
Let me prove this problem for you again. There is no diagram. I guess it is like this: R1 and R2 are connected in parallel, controlled by a switch s, single pole double throw, and connected in series with a constant resistance R. the power supply voltage is set to u
When the switch S is connected to position 1, R1 and R are connected in series at both ends of the power supply, with u = 0.2 (8 + R),
When the switch S is connected to position 2, R2 and R are connected in series at both ends of the power supply, with u = I (10 + R),
So 0.2 (8 + R) = I (10 + R), I = 0.2 (8 + R) / (10 + R),
(in high school, there is inequality a / B0, so 8 / 1010, so 0

Pyramid arrangement of natural numbers
As shown in the figure:
one
2 3 4
5 6 7 8 9
10 11 12 13 14 15 16
17 18 19 20 21 22 23 24 25
···
Q: what is the 26th number from right to left in line 25_ On line 38_ A word?

Look at the last number on each line
Line n should be n ^ 2
So the last one on line 25 is 25 ^ 2 = 625, and the 26th one on the left is 600
The number in line n is 2N-1
So line 38 has 2 * 38-1 = 75 numbers

When Xiao Ming studied the relationship between the voltage at both ends of the resistance and the current passing through the resistance, he found that when the resistance is constant, there are two resistances
The next topic is as follows:
The voltage at the terminal is proportional to the current passing through the resistor. Xiao Ming found a new rule after further analyzing the experimental data. In order to test whether the new rule he found is correct, he redesigned an experiment. The experimental data obtained are shown in the table below. Xiao Ming analyzed the experimental data in the table and thought that the new rule he found is correct.
R (Ω) 50 46 42 25 20 10
U (V) 14 12 10 8 6 4
I (A) 0.28 0.26 0.24 0.32 0.3 0.4
U/I (V/A) 50 46.2 41.7 25 20 10
(1) According to the experimental data in the table, it can be inferred that the new law discovered by Xiao Ming is as follows:
_。
(2) The new law discovered by Xiao Ming can be applied to electrical measurement. Please give an example of applying this law to measurement
。

1) This law is r = u / I, which is Ohm's law
2) Using this law, we can form a method of measuring resistance by voltage and current method. For example, in a digital multimeter, a constant current source (such as 1mA) is applied to the measured resistance, and the voltage reflected at both ends of the resistance is directly proportional to the measured resistance. In this way, the measured resistance can be obtained by measuring the voltage at both ends of the resistance

75 / 6, 1 / 3:5 / 12, 2 / 5kg: 500g, 9.6:6000, 8 / 9:10 / 8, 0.25:1 / 6

0.75/6 = 3:6 = 3:24 = 1:8 1 / 3:5 / 12 = 4:5 2 / 5kg: 500g = 400g: 500g = 4:5 9.6:6000 = 96:60000 = 1:625 8 / 9:10 / 8 = 64:90 = 32:450.25:1 / 6 = 1 / 4:1 / 6 = 6:4 = 3:2 ~ I wish you progress in your study ~ ~ ~ if you approve

In the circuit shown in the right figure, the power supply voltage remains unchanged, the resistance value of resistance R1 is 20 Ω, the indication value of table A1 is 0.3 A, and the indication value of ammeter A2 is 0.2 a
Find (1) power supply voltage U (2) resistance value of resistance R2 (3) power on for 10 seconds, the power of current through resistance R2

(1) According to Ohm's law, U1 = i1r1 = 0.3 a × 20 Ω = 6 v
According to the characteristics of parallel circuit, u = U1 = 6V
(2) According to the characteristics of parallel circuit, U2 = U1 = 6V
According to Ohm's law, R2 = U2 / I2 = 6 V / 0.2 a = 30 Ω
(3) W2 = u2i2t2 = 6 V × 0.2 a × 10 s = 12 J
Power P2 = W2 / T = 1.2W

Given that a is an integer and X, y is the integer solution of the equation x2-xy-ax + ay + 1 = 0, then X-Y= Or ．

The result is: X (X-Y) - A (X-Y) + 1 = 0, (X-Y) (x-a) = - 1, ∵ x, y, a are integers, ∵ X-Y = 1 or - 1, so the answer is - 1; 1

How many ohms is a megaohm
Please get a definite answer. I need to do my homework

10 ^ 6 ohm, that's a million ohm

Factorization: (y + 2) x ˇ 2 + (y + 2) x-12y-24