Party A and Party B have a total of 360 yuan. 25% of Party A's money and 20% of Party B's total is 80 yuan. How much does Party B have

Party A and Party B have a total of 360 yuan. 25% of Party A's money and 20% of Party B's total is 80 yuan. How much does Party B have

A + B = 360, 25% a + 20% B = 80, a = 200, B = 160

It is known that one root of the quadratic equation AX of one variable with respect to X is x = 2, then the value of 4a-6b is?

There are three numbers a, B and C. A is 2 larger than B and B is 11 larger than C. The average number of the three numbers is 70

Let C be x, then B be x + 11 and a be x + 13,
So x + (x + 11) + (x + 13) = 210,
Solve the equation: x = 62
So: A is 75, B is 73, C is 62

In linear algebra, what is the relationship between the rank of the augmented matrix and the rank of the original matrix? How to use it in judging whether there is a solution to a system of equations?

The properties of matrix rank: R (a) ≤ R (a, b) ≤ R (a) + R (b), R (b) ≤ R (a, b) ≤ R (a) + R (b)
So the relation between the matrix A of AX = B and the rank of (a, b) is: R (a) ≤ R (a, b) ≤ R (a) + R (b) = R (a) + 1. When AX = B has no solution, R (a) ≠ R (a, b), then R (a, b) = R (a) + 1

Party A, Party B and Party C complete a batch of parts. Party A and Party B complete 50% of the total tasks. Party A and Party C complete 3 / 5 of the tasks. Among them, Party A has made 360. How many of them are there?

A finished the whole task
50％＋3/5－1＝1/10
This batch of parts have
360 △ 1 / 10 = 3600

How to do the equation of 18-2 (3-4x) = 10x

18-2(3-4x)=10x
18-6+8x=10x
10x-8x=18-6
2x=12
x=6

There are two warehouses of Party A and Party B. the warehouse of Party A is three times of the warehouse of Party B. the warehouse of Party A takes 240 tons and the warehouse of Party B takes 40 tons. At this time, the stock of the two warehouses is equal

Let B have X tons, and a be 3x tons
3x-240=x-40
2x=200
x=100
B is 100 tons, a is 100 * 3 = 300 tons

9x-6x = 7 / 12

3x = 7 / 12
X = 7 / 12 / 3
X = 7 / 36

A simple calculation method of 44 × 22 + 33 × 4

44×22+33×4
=11×4×22+11×3×4
=11×88+11×12
=11×（88+12）
=11×100
=1100

The sum of the first n terms of an is Sn, A1 = 1; in BN, B1 = 1. If A3 + S3 equals 14, b2s2 = 12. Find an and BN. 2: let CN = an + 2bn (n belongs to N +), find the first n terms and TN of CN

(1) a3+S3=a3+3a2=14①
a3+S3=a1+a2+2a3=14,a1=1,a2+2a3=13②
From ① and ②, A2 = 3, A3 = 5, an = 2N-1
S2=4,b2S2=12,b2=3
b1=1 bn=3^(n-1)
(2)cn=2n-1+2*3^(n-1)
Tn=n²+3^n-1