I help my mother do housework

I help my mother do housework

I can do housework

I learned to do housework for the first time. In the morning, my mother and father went out for a run. I got up and felt very hungry. I opened the refrigerator to see if I had anything to eat. Except for the raw eggs, there was a pot of porridge on the stove and a handful of vegetables in the basket. Alas! If I waited for my mother and them to come back, I would be hungry

About my mother to do housework composition 400 words

A 300 word essay on housework

Today is Sunday, and it's our cleaning day. I was doing my homework and saw my mother sweating to clean. I couldn't bear it, so I quickly put down my pen and ran to help my mother do housework
We usually clean the windows, sweep the floor and mop the floor. First of all, we clean the windows. I put the cloth into the bucket filled with water to soak it. Then I found a chair and carefully stood on it to clean the glass. There was a thick layer of dust on the glass. I tried hard to clean it again and again. After my efforts, I finally cleaned the windows. Ah, I'm so tired!
After cleaning the windows, I'm going to sweep the floor. I found a broom, and then I bent my back, lowered my head, bent over, with a broom in my hand. I carefully swept every corner again and again, even a little paper scraps. Finally, I dumped a lot of garbage into the garbage can. In this way, the whole house was much cleaner
After sweeping the floor, I began to check the floor and found that there was still some dirt on the floor. So I found a mop, put it in a bucket filled with water and soaked it, and then dragged the floor seriously. I dragged the dirt again and again, and finally got rid of it. There was no dirt, but the floor turned into a "big face", and I couldn't clean it. At this time, I was very tired, My mother was very distressed when she saw me like this, so she handed me a towel and said, "child, you are so hard, don't do it." I listened to my mother's words, and I really want to quit. However, my mother was sweating all over the house immediately. I thought: my mother worked so hard for me every day, and what can I do with this hard work! Thinking of this, I said, "Mom, I'm not tired." then I continued to mop up the floor until the floor was clean. Through my efforts, the house was really clean
Although I'm exhausted, I'm happy to do housework for my mother

As shown in the figure, divide a parallelogram into four triangles, in which triangle a covers an area of 15 square centimeters, and triangle B covers 2 / 5 of the parallelogram
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Two of the four triangles are symmetrical, with the same area. If B takes up 2 / 5, the symmetrical one also takes up 2 / 5, and they take up 4 / 5. The remaining 1 / 5 is occupied by a and its symmetry, that is, 15 + 15 = 30 takes up 1 / 5 of the total area, so the area of the parallelogram is 30 * 5 = 150 square centimeters

If log (a) 2 > log (b) 2 > 0, then the size of AB is the same
If the function f (x) = log (2a) x + 1 defined in the interval (- 1,0) satisfies f (x) > 0, then the value range of real number a?
If log (a) 2

(1) Yin-1

After the formula of equation x2-3x + P = 0, we get (x + m) 2 = 12. (1) find the value of constant P and m; (2) find the root of the equation

(1) ∵ x2-3x + P = 0, ∵ x2-3x = - P, x2-3x + (32) 2 = - P + (32) 2, (x-32) 2 = - P + 94, ∵ M = - 32, - P + 94 = 12, the solution is: P = 74, M = - 32; (2) ∵ x2-3x + P = 0, ∵ x-32) 2 = 12, x-32 = ± 22, that is, the solution of the equation is: X1 = 3 + 22, X2 = 3 − 22

Make two tangent lines of circle C: (x-44) ^ 2 + (Y-2) ^ 2 = 9 through P (1,0). The tangent points are a and B. solve the equation of PA and Pb
D

Is it (x-4) ^ 2 + (Y-2) ^ 2 = 9?
Center (4,2), r = 3
The distance from the center of the circle to the tangent is equal to the radius
If the tangent slope does not exist, it is perpendicular to the x-axis
That is, x = 1, the distance from the center of the circle to the tangent is 4-1 = 3 = R
If the slope exists
Then y-0 = K (x-1)
kx-y-k=0
The distance from the center of the circle to the tangent is equal to | 4k-2-k | / √ (k ^ 2 + 1) = 3
|3k-2|=3√(k^2+1)
Square on both sides
9k^2-12k+4=9k^2+9
k=-5/12
5x+12y-5=0
To sum up
X-1 = 0 and 5x + 12y-5 = 0

It is known that the focal point of the parabola y = (1 / 4) x ^ 2 is F. two tangent lines of the parabola are made through a point m on its directrix L. the tangent points are a and B,
(1) Proof: xaxb = - 4
(2) It is proved that the line AB is always over the fixed point F
(3) Under the conclusion of (2), the minimum area of △ ABM and the coordinates of point m are obtained

1. Finally came out y = (1 / 4) x ^ 2, obtained its directrix is y = - 1, let the point on the directrix be m (m, - 1) let a (a, 1 / 4A ^ 2) B (B, 1 / 4B ^ 2) the parabolic derivative is y '= 1 / 2x, then the parabolic equation passing through a point is y = 1 / 2A (x-a) + 1 / 4A ^ 2, and m point is on the straight line, so - 1 = 1 / 2A (M-A) + 1 / 4A ^ 2 [1] similarly - 1 =

In square ABCD, e is on CD, and AE = CE + BC, M is the midpoint of CD, and ∠ BAE = 2 ∠ dam is proved
Sorry, there's no picture

Prove: take the midpoint of BC as O, connect AO and extend, and cross the extension line of DC to point F
Easy syndrome △ ABO ≌ △ FeO
∴CF=AB=BC
∵AE=CE+BC
∴AE=CE+CF=EF
∴∠F=∠EAF
∵∠F=∠BAO
∴∠BAE=2∠BAO
∵AB= AD.BO=DE ,∠D=∠B
∴△DAM≌△BAD
∴∠DAM=∠BAO
∴∠BAE=2∠DAM