Help mother do housework on women's Day (600 words)

Help mother do housework on women's Day (600 words)

Help mother do housework on women's Day
Content specific -- Feeling -- quick!

Tomorrow is March 8 women's day. I always want to do something for my mother, but I don't have the chance. Today is a good opportunity for me to do something for my mother. My mother has never asked me to do anything for her. I must give her a surprise today. In the evening, my mother came back, and I quickly went to the kitchen to soak well

Do you have a good way to find the solution of 361x + 463y = − 102463x + 361y = 102?

① + 2: 824x + 824y = 0, x = - y 3, substituting 3 into 1: 102y = - 102, the solution is y = - 1, so x = 1. X = 1y = − 1

It is known that the circle C: x ^ 2 + y6 ^ 2 + 2x-4y + 1 = 0, O is the coordinate origin, the moving point P is outside the circle C, the tangent of the circle C is made through P, and the tangent point is m
1. If point P moves to (1,3), find the equation of tangent L
2. Find the trajectory equation satisfying the condition | PM | = | Po |
Urgent request, who can help, I have been waiting online

1. If point P moves to (1,3), the equation of tangent L is as follows:
x=1 ,y= -(3/4)x + 15/4

Calculation, (1 / 8 + 1 / 9 + 1 / 10 + 1 / 11) x (1 / 9 + 1 / 10 + 1 / 11 + 1 / 12) - (1 / 8 + 1 / 9 + 1 / 10 + 1 / 11 + 1 / 12) x (1 / 9 + 1 / 10 + 1 / 11)

Let (1 / 8 + 1 / 9 + 1 / 10 + 1 / 11) = a, 1 / 9 + 1 / 10 + 1 / 11 = B
a（b+1/12）-（a+1/12）*b
=（a-b）/12
=(1/8)/12
=1/96

The value of the algebraic formula 3x square-12x + 13 is not less than 1

3x²-12x+13
=3(x²-4x+13/3)
=3(x-2)²+1
Because 3 (X-2) & 178; ≥ 0
So 3 (X-2) ² + 1 ≥ 1
So the value of the algebraic formula 3x square-12x + 13 is not less than 1

What are negative 1 / 2 plus 3 and negative 1 / 2 minus 3 respectively

-1/2+3=2.5
-1/2-3=-3.5
Two and one in two
-Three and one in two

3x+4y=18,2x-3y=-5

3x+4y=18 (1)
2x-3y=-5 (2)
(1)×3+(2)×4
9x+12y+8x-12y=54-20
17x=34
therefore
x=2
y=(2x+5)/3=3

Find the analytic expression of function if f (x): the equation f (X-Y) = f (x) - Y (2x-y + 1) holds for all real numbers x and y, and f (0) = 1

Because it holds for all real numbers x, y
Let x = y
Then f (X-Y) = f (x) - Y (2x-y + 1)
Equivalent to f (0) = f (x) - x (2x-x + 1)
And because f (0) = 1
So f (x) - x (2x-x + 1) = 1
The solution is f (x) = x ^ 2 + X + 1

Calculation of 1-1 + X fraction of 1-x

1/(1-x)-(1-x)=[1-(1-x)²]/(1-x)=(2
x-x²)/(1-x).