My weekend 200 words 400 words

My weekend 200 words 400 words

The weekend is coming.
I will have a happy weekend.
On Saturday morning,I’m going to do my homework.And then,I’m going out to play.I’m going to the bookstore and read some books.In the evening,I am going to have dinner with my parents outside.On Sunday morning,I’m going to the library or do my homework.And then,I’m going to listen to music.In the afternoon,I’m going to go shopping with my mother.I like shopping very much.
This is my happy and busy weekend.Do you like this weekend?

Sometimes I will help my mother do housework

Sometimes,I will help my mother do some housework.

Chen Jie often helps her mother do housework

Chen Jie aways helps hermother do housework.

Can wind turbines convert the captured wind energy into electrical energy or chemical energy and charge them into their own batteries for storage

The wind energy drives the fan to rotate and convert it into mechanical energy. The fan drives the internal coil to cut the magnetic induction line. The mechanical energy is converted into electric energy. The electric current causes the chemical reaction in the battery, and the electric energy is converted into chemical energy. Therefore, the wind energy is converted into chemical energy. Battery charging is the conversion of electric energy into chemical energy, and battery discharging is the conversion of chemical energy into electric energy

The ordinate of the intersection point between the image with positive scale function y = x and the image with inverse scale function y = K / X is 2
(1) When x = 3, the value of inverse proportional function y
(2) When - 3 ＜ x ＜ - 1, the value range of inverse proportional function y

Y=X ,Y=K/X
There is an intersection whose ordinate is 2
The solution is (2,2), substituting (2,2) into y = K / X
The solution is k = 4
When x = 3, substitute x = 3 into y = K / X
y=4/3
When - 3 ＜ x ＜ - 1, substitute x = - 3 x = - 1 into y = K / X
y=-4/3 y=-4
So - 4

How many kilos of meat is 1100 calories

1 / 7, every 7700 calories is a kilo

If x2-13x + 1 = 0, then the digit of X4 + 1x4 is ()
A. 1B. 3C. 5D. 7

From the equation x2-13x + 1 = 0, we can get x = 13 ± 169 − 42 = 13 ± 1652, divide both sides of the equation by X, then we can get x + 1x = 13, then we can square both sides of the equation; we can get x 2 + 1x2 = 167, then we can square both sides of the equation; we can get x 4 + 1x4 = 27889-2 = 27887

Calculation formula of superconductor current
In the case of voltage, I should be U / R, but r of superconductor is 0
So what is the specific calculation formula
Then, in the case of no load, I is not infinite

Calculation by power of load
P=UI
I=P/U

When an object is moving in a straight line with uniform acceleration, the initial velocity is 0.5m/s, and the displacement in the 7th second is 4m more than that in the 5th second. The calculation is as follows: (1) the acceleration a of the object with uniform acceleration; (2) the displacement of the object in the first 5S

(1) According to X7 − X5 = 2at2, the acceleration is: a = X7 − x52t2 = 42 × 1 = 2m / S2. (2) the displacement of the object in the first 5S is: x = v0t + 12at2 = 0.5 × 5 + 12 × 2 × 25m = 27.5m

All the formulas and units of junior high school physics,

1. Heat: heat absorption (heat release): q = cm △ t (Q: heat absorption and heat release, unit: Joule (J); C: specific heat capacity, unit: J / kg ℃; Δ T: temperature change, unit: ℃)
Heat balance equation: Q discharge = q suction (excluding heat loss, the heat released by high temperature body is equal to the heat absorbed by low temperature body)
Heat engine efficiency η = qyou / qtotal
2. Electricity: Ohm's Law: I = u / R (I: current, unit: Ampere (a); U: voltage, unit: volt (V); R: resistance, unit: Ohm (Ω)
Series circuit characteristics: A, current characteristics: I = I1 = I2 = =In (current is equal everywhere)
b. Voltage characteristics: u = U1 + U2 + +UN (the total voltage is equal to the sum of the voltages of each part)
c. Resistance characteristics: r = R1 + R2 + +RN (the total resistance is equal to the sum of the resistances of each part)
d. Partial voltage characteristics: U1 / U2 = R1 / r2 or UN / u = RN / R (the distribution of voltage is proportional to the resistance)
Parallel circuit features: A, current features: I = I1 + I2 + +In [total (trunk) current equals the sum of branch currents]
b. Voltage characteristics: u = U1 = U2 = =UN (voltage at both ends of each branch is equal)
c. Resistance characteristics: 1 / r = 1 / R1 + 1 / r2 + +1 / RN (the reciprocal of the total resistance is equal to the sum of the reciprocal of each branch resistance)
d. Shunt characteristics: I1 / I2 = R2 / R1 or I / in = RN / R (current distribution is inversely proportional to resistance)
Electrical work: w = uit (= square of current times resistance times time = square of voltage times time divided by resistance = Qu) [q is the amount of charge, unit: Coulomb (c); W: electrical work, unit: Joule (J); t: time, unit: second (s)]
Electrical power: P = w / T = UI (= square of current multiplied by resistance = square of voltage divided by resistance) [P: electrical power, in watts (W)]
Electric heating: q = w
3. Mechanics:
a. Mass and density: M = ρ v [M: mass in kg; ρ: density in kg / m3; V: Volume in m3]
b. Uniform linear motion: S = VT [S: distance, m; V: speed, M / S; t: time, S]
c. Resultant force of two forces in the same direction on the same line: F = F1 + F2 [f; resultant force, unit: Newton (n)]
d. Resultant force of two opposite forces on the same straight line: F = F1-F2 (F1 > F2)
e. Pressure: P = f / s [P: pressure, unit: Pascal (PA); F: pressure, unit: Newton (n); s: stressed area, unit: square meter (m ^ 2)]
f. Internal pressure of liquid: P = ρ GH [P: pressure; ρ: density; H: depth of pressure point, unit: M]
g. Buoyancy: F floating = g row [(g row: weight of liquid or gas, unit: Newton (n)]
=F lower - f upper (f lower: upward pressure on the lower surface of the object, f upper: downward pressure on the upper surface of the object) = ρ liquid GV row (ρ liquid: liquid density; G: constant, 9.8n/kg; V row: volume of the liquid)
h. Lever balance condition: F1 × L1 = F2 × L2 (F1: power; F2: resistance; unit: Newton; L1: power arm; L2: resistance arm; unit: meter)
i. Power in pulley block: F = gtotal / N (F: tension at free end of rope, gtotal: total weight of object and movable pulley; N: number of rope segments bearing movable pulley) (excluding friction between rope and pulley)
j. Slope: FL = GH (F: force along the slope, l: slope length; G: weight; H: slope height)
k. Work: w = FS [w: work, in joules (J); F: force acting on the object, in Newtons (n); s: distance of the object moving in the direction of the force, in meters (m)]
l. Power: P = w / T = FV [P: power, in watts (W); W: work, in joules (J); t: time, in seconds (s); F: force doing work, in Newtons (n); V: velocity of the object, in meters per second (m / s)]
m. Mechanical efficiency: η = w yes / W total = P yes / P total [η: mechanical efficiency, no unit; W yes: active work, unit Joule (J); W total: total work, unit Joule (J); P yes: useful power, unit watt (W); P total: total power, unit watt (W)]
Basically, that's all. I hope it can help you