(1 / 2) Xiao Gang read a story book. He read 56 pages every day. After 4 days, he happened to read 8 / 11 of the whole book. How many pages are there in this book? How many pages are left (1 / 2) Xiao Gang read a story book. He read 56 pages a day. After 4 days, he happened to read 8 / 11 of the whole book. How many pages are there in this book? How many pages are there left? (don't make equations, just send me the formulas

(1 / 2) Xiao Gang read a story book. He read 56 pages every day. After 4 days, he happened to read 8 / 11 of the whole book. How many pages are there in this book? How many pages are left (1 / 2) Xiao Gang read a story book. He read 56 pages a day. After 4 days, he happened to read 8 / 11 of the whole book. How many pages are there in this book? How many pages are there left? (don't make equations, just send me the formulas


A total of 56 * 4 / (8 / 11) = 304, the remaining 304-56 * 4 = 80



There are only three story books and five science and technology books in the bookcase. How many books should you take out at least if you want to take two story books at a time?


5 + 2 = 7 A: at least 7 books



There are three story books and five science and technology books mixed in the bookcase. To ensure that we can take out two science and technology books at a time, how many books should we take out at least at a time


To ensure that we can take out two scientific and technological books at a time, we should consider the most unfavorable situation, that is, if we take out all the non scientific and technological books and then get the scientific and technological books, we need to take out 3 + 2 = 5 books, we can take out two scientific and technological books
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1/6,2/3,3/2 ,8/3 ,( )A,10/3 B,15/4 C,5 D,92/6


Unify denominators
1/6 ,4/6 ,9/6 ,16/6
Observe molecules 1, 4, 9, 16
If the difference is 3,5,7, then the difference between the next item and the previous item is 9, which is 25, and the next item is 25 / 6



Two exactly the same right angle trapezoid into a rectangle, the area is 300 square centimeters, one of the trapezoid area is___ Square centimeter


A: the area of each trapezoid is 150 square centimeters. So the answer is: 150



The solution set of x ^ (lgx + 1) - 100 = 0 is?


The original equation can be changed to 10 ^ ((lgx + 1) lgx) = 10 & sup2;
So we have (lgx + 1) lgx = 2
There is LG & sup2; X + lgx - 2 = 0
This can be regarded as a quadratic equation of one variable about lgx
The solution is lgx = - 2 or lgx = 1
So x = 10 ^ (- 2) = 0.01 or x = 10 ^ 1 = 10
So the solution set of the equation is {0.01,10}



There is a child holding a bamboo pole to pass through a rectangular door. If the bamboo pole is placed vertically, it is 1 foot higher than the door. If it is placed obliquely, it is exactly equal to the diagonal line of the door. Given the width of the door is 4 feet, calculate the height of the bamboo pole and the height of the door


Let the gate height be x feet, then the bamboo pole length be (x + 1) feet. According to the Pythagorean theorem, we can get: x2 + 42 = (x + 1) 2, that is, X2 + 16 = x2 + 2x + 1, the solution is: x = 7.5, so the gate height is 7.5 feet, and the bamboo pole height is 7.5 + 1 = 8.5 feet



A polynomial (17x2-3x + 4) - (AX2 + BX + C) is divided by (5x + 6), and the quotient is (2x + 1), the remainder is 0. The value of a-b-c is obtained


∵ polynomial (17x2-3x + 4) - (AX2 + BX + C), divided by (5x + 6), the quotient is (2x + 1), the remainder is 0, ∵ 17x2-3x + 4) - (AX2 + BX + C) = (5x + 6) (2x + 1), that is, (17-a) x2 + (- 3-B) x + (4-C) = 10x2 + 17x + 6, ∵ 17 − a = 10 − 3 − B = 174 C = 6, the solution is: a = 7, B = - 20, C = - 2, ∵ a-b-c = 7 - (- 20) - (- 2) = 29



Xiao Li's family has a triangular wheat field, 56m at the bottom and 35m at the height. How many square meters is the area of this wheat field?
It's the area of the triangle in the fifth grade mathematics exercise book of pep!


Bottom times high, divided by two, that's it
(56 times 35) divided by 2 = 1960 divided by 2 = 980 (m)!



It is known that log (3) 2 = a, log (5) 2 = B, and ab denotes log (30) 90


If the number in brackets is true,
Then log (30) 90
=[log(30)2]/[log(90)2]
=[log(2)2+log(3)2+log(5)2]/[log(2)2+2log(3)2+log(5)2]
=(1+a+b)/(1+2a+b).
If the base number is in brackets,
Then log (30) 90
=[log(2)90]/[log(2)30]
=[log(2)2+2log(2)3+log(2)5]/[log(2)2+log(2)3+log(2)5]
=(1+2/a+1/b)/(1+1/a+1/b)
=(ab+a+2b)/(ab+a+b).