Help me solve a math problem and answer it in a minute! When Li Mengmeng read a book, he read one third of the whole book on the first day, and 18 pages more than 25% of the whole book on the second day. At this time, the ratio of the number of pages read to the number of pages not read is 3:1. (1) how many pages are there in the book? (we can't use equations to solve it, we must use equations) (2) how many pages did he read the next day?

(1)18/(3/4-1/4-1/3)=108
(2)108*1/4+18=45

For a project, team a alone will take 8 days to complete and team B alone will take 12 days to complete. If the two teams work together in one day, how many parts of the project will be completed?

18 + 112 = 524; a: a total of 524

In a minute!
17 out of 18 - (17 out of 18-7 out of 25) it is said that there are nine birds with nine heads and one tail, and nine birds with nine tails and one head. It is known that there are 590 heads and 510 tails in a group of nine head birds and nine tail birds. How many of the two kinds of birds are there?

Suppose there are x nine birds
Then, there are (590-9x) and {(510-x)} nine tailed birds
Therefore, 590-9x = (510-x) 9
X=60
Therefore, there are 60 nine headed birds and (590-9 * 60 = 50) nine tailed birds

How many minutes is an hour in five?

60÷5＝12
12×1=12

(1-1/2+1/3-1/4+...+1/99-1/100)/(1/101^2-1^2+1/102^2-2^2+...+1/150^2-50^2)

Molecules
=（1+1/2+1/3+1/4+…… +1/99+1/100）-2*（1/2+1/4+…… +1/100）
=1+1/2+1/3+..+1/100-(1/1+1/2+1/3+...+1/50)
=1/51+1/52+… +1/99+1/100
denominator
=1/(100-1)(101+1)+1/(102-2)(102+2)+...+1/(150-50)(150+50)
=1/100(1/102+1/104+...+1/200)
=1/200(1/51+1/52+...+1/100)
So,
The original formula = (1 / 51 + 1 / 52 +...) +1/99+1/100)/[1/200(1/51+1/52+...+1/100)]
=1/(1/200)
=200

If the sum of the cubic power of the polynomial 2x-2x-2x + X and the cubic power of the polynomial x-5x + 2mx + 3 does not contain a quadratic term, then the constant M =?

Sum = 2x & # 179; + (2m-8) x & # 178; - 4x + 3
If there is no quadratic term, then the coefficient is 0
2m-8=0
m=4

In a store, the purchase price of a product is 2000 yuan per piece. If the product is sold at 80% of the price, the profit of each product will be reduced by 60%______ Yuan

Suppose the price of goods is x yuan, x-80% x = 60% (x-2000) x = 3000, so the price of goods is 3000 yuan

205+203-201-199+197+195-193-191+.+101+99-97-95

205+203-201-199+197+195-193-191+189+.-103+101+99-97-95=205+(203-201)-(199-197)+(195-193)-(191-189)+.-(103-101)+(99-97)-95=205+2-2+2-2+...-2+2-95=205+2-95=112

Y = (arcsin √ (x-1)) ^ 2, find the derivative of Y

y = [arcsin√(x - 1)]²
y' = 2•arcsin√(x - 1) • [arcsin√(x - 1)]'
= 2arcsin√(x - 1) • 1/√{1 - [√(x - 1)]²} • [√(x - 1)]'
= 2arcsin√(x - 1) • 1/√(2 - x) • 1/[2√(x - 1)] • (x - 1)'
= 2arcsin√(x - 1) • 1/√(2 - x) • 1/[2√(x - 1)] • 1
= [arcsin√(x - 1)]/√[(2 - x)(x - 1)]