Let's go to the cinema together on Sunday, () you come to ask me out, () I'll ask you out

Let's go to the cinema together on Sunday, () you come to ask me out, () I'll ask you out

You come to ask me out. I'll ask you out

36 times 18 = {36 divided by 3} times {18 times} = {}

36 times 18 = {36 divided by 3} times {18 times 3} = {648}

The area of two similar triangles is 9 square centimeter and 25 square centimeter respectively. The perimeter difference between them is 6cm, so the perimeter of the larger triangle is 6cm

If the area ratio of similar triangle is 9:25, then the similarity ratio is 3:5, that is, the perimeter ratio is 3:5, and the perimeter difference is 6. If the larger perimeter is x, then (X-6) / x = 3:5
The solution is: x = 15
The larger perimeter is 15

How to calculate (0.81 * 0.75 * 0.48) / (0.25 * 0.24 * 0.27)

(0.81*0.75*0.48)/(0.25*0.24*0.27)
=(0.81/0.27)x(0.75/0.25)x(0.48/0.24)
=3x3x2
=18

The area of a trapezoid is 2.52 square meters, the height is 0.6 meters, the bottom is 2.4 meters, and how many meters is the upper bottom?

Area of trapezoid = (upper bottom + lower bottom) * height / 2
Upper bottom = area * 2 / height - lower bottom
2.52 * 2 / 0.6-2.4 = 6M

X / 20 = (12-x) / 12 to solve the equation

Double 60
3x=5(12-x)
3x=60-5x
3x+5x=60
8x=60
x=60÷8
x=7.5

The area of a parallelogram and a triangle with equal base and equal height is that of a parallelogram (). The area of a parallelogram is () more than that of a triangle
Urgent, urgent, urgent

A parallelogram and a triangle have the same base and height. The area of a triangle is 1 / 2 of that of a parallelogram. The area of a parallelogram is 100% larger than that of a triangle

At - 49, - 48, - 47 In 2003, the sum of the first 99 consecutive integers in a series of numbers is? The sum of the first 100 consecutive integers is?
Urgent!

The first 99 consecutive integers are - 49, - 48,..., 48, 49, and their sum = (49-49) + (48-48) +. + (1-1) + 0 = 0 + 0 + 0 +. + 0 = 0
The first 100 consecutive integers are - 49, - 48,..., 49, 50, and their sum = (49-49) + (48-48) +. + (1-1) + 0 + 50 = 0 + 0 + 0 +. + 0 + 50 = 50

As shown in the figure, it is known that in the triangle ABC, points D and E are on sides AB and AC respectively, connecting de and extending the extension line of intersection BC to point F, connecting DC and be
And the angle BDC + angle BCE = 180 degrees, prove that the triangle FDC is similar to the triangle FBE

The feeling is that ∠ BDE + ∠ BCE = 180 quadrilateral diagonal complementation 〉 bdec is four point common circle 〉 FDC = ∠ FBE (the same arc of EC to the circumference angle is equal) 〉 △ FDC ∽ FBE or ∵ BDE + ∠ BCE = 180 °∠ ECF + ∠ BCE = 180 °∠ BDE = ∠ ECF, ∽ BDF ∽ ECF, ∽ BF / EF = DF / CF, ∽ BF / DF = ef

Given a b c r, and a + B = C + D = 1, AC + BD > 1, we prove that at least one of a B C D is negative
Urgent,

There are many cases in which at least one of a, B, C, D is negative, but there is only one case on the opposite side. Therefore, we should consider using the counter proof method to prove that: suppose that a, B, C, D are all non negative numbers, ∵ a + B = C + D = 1, ∵ (a + b) (c + D) = 1, that is, (AC + BD) + (a