Xiao Ming borrowed 1000 yuan from his parents, bought a pair of shoes, used 970 yuan, and left 30 yuan. He gave 10 yuan to his father, 10 yuan to his mother, and 10 yuan to himself. So he still had 490 yuan to his father and mother, a total of 980 yuan, and his 10 yuan was only 990 yuan. Why?

Xiao Ming borrowed 1000 yuan from his parents, bought a pair of shoes, used 970 yuan, and left 30 yuan. He gave 10 yuan to his father, 10 yuan to his mother, and 10 yuan to himself. So he still had 490 yuan to his father and mother, a total of 980 yuan, and his 10 yuan was only 990 yuan. Why?


If you add 10 yuan, it's more than enough. If you add 10 yuan to your shoes, 970 + 10 = 980 is the money spent. In fact, you borrow 980 yuan



Xiao Ming borrowed 500 from his father and 500 from his mother, a total of 1000. He bought a pair of shoes for 970 yuan and 30 yuan. He returned 10 yuan to his father, 490 yuan to his father, 10 yuan to his mother, 490 yuan to his mother, and 10490 + 490 + 10 = 990 yuan. Where is 10 yuan?


Xiao Ming borrowed 500 and paid back 10, which is equivalent to borrowing 490 each. Right? 490 times 2 equals 980. It cost 970980-970 = 10 to buy shoes. Here is 10 yuan



Today is Xiao Ming's good friend Li Ping's birthday. He invited Xiao Ming to have dinner at her home in the evening. Xiao Ming came back to school just to tell his mother
Xiao Ming
mom:
Xiao Ming
mom:


When parents want their children to make friends with good classmates, they can make progress together, but they should have good moral character and self-motivated. At the same time, they should win the approval of their parents



Xiao Gang read a story book. He planned to finish it in 10 days, but actually read 5 more pages every day. As a result, he finished it 2 days ahead of schedule. How many pages did he plan to read every day?
Let the original plan look at page X. The equation is as follows:


10X=(5+X)(10-2)



What's 83 times 9 / 84?


83x84 9 = 84x84 9-84 9 = 9-84 9 = 8 and 84 75



Y = | x | finding the limit of LIM [f (x) / x] x approaching zero


The left limit is equal to - 1 and the right limit is equal to 1



It is known that the solution of the equation 3A + x = ax + 3 is x = 4, and the value of a is obtained


3A + x = ax + 3 of 2
Substitute x = 4 in
3A + 4 = 2 of a * 4 + 3 = 2A + 3
a=-1



Calculation of 436-37-63 by simple method


436-(37+63)
=436-100
=336



Calculate 27 ^ n ﹣ 9 ^ n ﹣ 3


27^n÷9^n÷3
=(3³)^n÷(3²)^n÷3
=3^3n÷3^2n÷3
=3^(3n-2n-1)
=3^(n-1)



After dividing a polynomial [(x ^ 2-5x + 6) - (AX ^ 2-bx + C)] by 3x, the quotient is 2x + 1, the remainder is 0, and the value of a + B + C is obtained


After dividing a polynomial [(x ^ 2-5x + 6) - (AX ^ 2-bx + C)] by 3x, the quotient is 2x + 1, and the remainder is 0,
[(x^2-5x+6)-(ax^2-bx+c)]=3x(2x+1)
x^2-5x+6-ax^2+bx-c=6x^2+3x
(1-a)x^2+(b-5)x+6-c=6x^2+3x
(1-a)=6 (b-5)=3 6-c=0
a=-5 b=8 c=6
a+b+c
=-5+8+6
=9