The circumference of the bottom of the cuboid is 36 cm and the height is 8 cm. The total length of the edges of the cuboid is () cm

The circumference of the bottom of the cuboid is 36 cm and the height is 8 cm. The total length of the edges of the cuboid is () cm

36 * 2 + 8 * 4 = 104, two sides at the bottom, a total of 8 edges, plus four heights

A cuboid is 10 cm long, 8 cm wide and 5 cm high. Cut it into two cuboids. What is the maximum sum of the surface area of the two cuboids?

(10 × 8 + 10 × 5 + 8 × 5) × 2 + 10 × 8 × 2, = 340 + 160, = 500 (square centimeter). A: the maximum sum of the surface areas of these two cuboids is 500 square centimeter

When a cuboid with a length of 8 cm, a width of 6 cm and a height of 4 cm is cut into two cuboids, the sum of the surface areas of the two cuboids is the largest

[analysis] if a cuboid is cut into two cuboids, two cross sections will be added. If the sum of the surface areas of the two cuboids is the largest, the increased cross section is length × height = 8 × 6 = 48 square cm. The surface area of the original cuboid is 2 × (8 × 6 + 8 × 4 + 6 × 4) = 208 square cm. The increased surface area is 8 × 6 × 2 = 96 square cm

Both books are prime numbers. The sum of the two numbers is 15. The product of the two numbers is 26. What are these two numbers?

Answer: 2 and 13
Analysis: the product of two numbers 26 has 1 and 26, 2 and 13. According to the sum of two numbers is 15, the two prime numbers are 2 and 13 respectively

Given the function f (x) = loga (AX - √ x) (1) if a = 1 / 2, find the solution of the equation f (x) + 2 = 0 (2) if the function f (x) monotonically decreases in (2, + ∞), find the value range of a

1. If a = 1 / 2, find the equation f (x) + 2 = 0, that is Log1 / 2 (1 / 2x - √ x) = - 21 / 2x - √ x = 4x = 1 / 4x ^ 2-4x + 16x ^ 2-20x + 64 = 0, X1 = 4, x2 = 161 / 2x - √ x > 0, x = - 4x = 162. If the function f (x) monotonically decreases in (2, + ∞), find the value range of a, let √ x = b > 0, AB ^ 2-B, the axis of symmetry is 1 / 2AA > 0, there must be ab

If a > 0, a is not equal to 1, compare the logarithm of a ^ 3-A + 1 with that of a ^ 2-A + 1

(a^3-a+1)-(a^2-a+1)=a^2(a-1)
When 0 (a ^ 2-A + 1),
log(a)[a^3-a+1]>log(a)[a^3-a+1]

The solution of the equation x + 2Y = 4, 2x + 3Z = 13, 3Y + Z = 6
x+2y=4
2x+3z=13
3y+z=6
Process, thank you

Set the upper part as (1) (2) (3) respectively
Make 1 * 2 2x + 4Y = 8 (4)
Using (2) - 4, 3z-4y = 5 (5)
LIANLI (3)
Get 9y + 3Z = 18 from (3) * 3
Then y = 1 can be obtained by using (5) - 3 * 3
Then we bring in x = 2, z = 3

Let the probability density function of two-dimensional random variable (x, y) be f (x, y) = 4.8y (2-x), and find the probability of X + Y & lt; = 1

There are other conditions. No, the conditions you give seem inadequate

Simple function of MATLAB
Why do I use simple or simplify to simplify G2 = ((2 * x + 1) ^ 3 / x ^ 3) ^ (1 / 3), instead of G2 = (2 * x + 1) / X or G2 = 2 + 1 / x

Since 2008b, the symbolic operation core of Mtalab has been changed from maple to mupad. According to most people's opinion, maple is much better than mupad. Therefore, if you use more symbolic operation, you'd better use the version before 2008a. & nbsp; as far as this problem is concerned, I have tested it on 6.5, 2007b and 2013a, The first two results are OK: & gt; & gt; & nbsp; Syms & nbsp; X & gt; & gt; & nbsp; G2 & nbsp; = ((2 * X & nbsp; + & nbsp; 1) ^ 3 / x ^ 3) ^ (1 / 3) G2 & nbsp; = ((2 * x + 1) ^ 3 / x ^ 3) ^ (1 / 3) & gt; & nbsp; G3 = simple (G2) G3 & nbsp; = (2 * x + 1) / X & gt; & gt; & nbsp; G4 = simple (G3) G4 & nbsp; = 2 + 1 / X, The reason is that the simple function tries many kinds of algebraic simplification methods and gets the most concise expression from it. But in some cases, the most concise expression is often obtained through two kinds of transformations. For example, the above two simple functions, the first one is through radsimp method, the second one is through collect, expand and other methods; But there are some problems in 2013a (mupad kernel): & gt; & gt; & nbsp; Syms & nbsp; X & gt; & gt; & nbsp; G2 & nbsp; = ((2 * X & nbsp; + & nbsp; 1) ^ 3 / x ^ 3) ^ (1 / 3) G2 & nbsp; = ((2 * X & nbsp; + & nbsp; 1) ^ 3 / x ^ 3) ^ (1 / 3) & gt; & gt; & nbsp; G3 = simple (G2) G3 & nbsp; = ((2 * X & nbsp; + & nbsp; 1) ^ 3 / x ^ 3) ^ (1 / 3) ^ (1 / 3)

How much is eight yuan and twenty cents

Eight yuan and twenty cents