A horizontal cuboid with a side length of 8 cm and a height of 3.5 cm is on the bottom. What is the surface area and volume of the cuboid?

A horizontal cuboid with a side length of 8 cm and a height of 3.5 cm is on the bottom. What is the surface area and volume of the cuboid?

Surface area = 8 × 3.5 × 4 + 8 × 8 × 2 = 240 square centimeter
Volume = 8 × 8 × 3.5 = 224 CC

A cuboid wood, the bottom is an 8 cm long square, 5 meters long, which is related to the volume of wood is [], the surface area is []

5 m = 500 cm
8 * 8 * 500 = 32000 (cm3) volume
(8 * 8 + 8 * 500 + 8 * 500) * 2 = 16128 (square centimeter) Surface area
A cuboid wood, with a side length of 8 cm and a length of 5 m on the bottom, has a volume of [32000 cubic cm] and a surface area of [16128 square cm]

If a > 2, then the function f (x) = 1 / 3x ^ 3-ax ^ 2 + 1 has just a few zeros in the interval (0,2). Please draw a picture and explain in detail,

First, the derivative f (x) = x (x-2a) is obtained. Because a > 2, f (x) decreases monotonically in (0,2), f (0) = 1, f (1) = 4-3-a

Partition x ^ 2 = 2x + 1 / 1-x ^ 2

The original formula = (1 + x) & # / (1 + x) (1-x)
=(1+x)/(1-x)

Mathematical solution of a quadratic equation of one variable is very simple
250+250（1+X）+250（1+X）^2=843.6
I can't stand it. I haven't solved it yet

250＋250（1＋X）＋250（1＋X）²＝843.6250（1＋X）²＋250（1＋X）－593.6＝025（1＋X）²＋25（1＋X）－59.36＝025（1＋X）²＋25（1＋X）＋6.25－6.25－59.36＝0[5（1＋X）＋2.5]²＝65.615...

The decomposition factor 6x ^ 3 + 5x ^ 2-7 / 3x ^ 2-2x-1 is the sum of partial fractions

6X & sup3; + 5x & sup2; - 7 / 3 * X & sup2; - 2x-1 = 6x & sup3; + 8 / 3 * X & sup2; - 2x-1 = 6x & sup3; - 2x + 8 / 3 * X & sup2; - 1 = 2x (3x & sup2; - 1) + 8 / 3 * X & sup2; - 1 = 2x (x √ 3 + 1) (x √ 3-1) + (2x √ 2 / √ 3 + 1) (2x √ 2 / √ 3-1) x placed before root sign and fraction means not in root sign and not

Given | X-5 | + | y + 2 | = 0, find the value of 1y of 2x + 2

x=5 y=-2 -1/6

Let the rank of the coefficient matrix of the second linear system of equations with n unknowns and M equations be r. the necessary and sufficient condition for a homogeneous linear system to have nonzero solutions is r

Is less than N, that is, the number of unknowns, or the number of columns of the coefficient matrix

If ax + 2 + BX − 3 = 7x − 11x2 − x − 6, try to find the value of a and B

∵ ax + 2 + BX − 3 = a (x − 3) + B (x + 2) (x + 2) (x − 3) = ax − 3A + BX + 2bx2 − x − 6 = (a + b) x + (− 3A + 2b) x2 − x − 6 = 7x − 11x2 − x − 6, ← a + B = 7 − 3A + 2B = − 11, the solution is: a = 5, B = 2

Given the absolute value of B-2 + (a + B-1) ∧ 2 = 0, find the value of a ∧ 50 △ A8

It is known that | B-2 | + (a + B-1) ^ 2 = 0,
And there are: | B-2 | ≥ 0, (a + B-1) ^ 2 ≥ 0,
The results show that B-2 = 0, a + B-1 = 0,
The solution is: B = 2, a = - 1,
So, a ^ 50 △ B ^ 8 = 1 / 256