Fill a square glass jar with water whose edge length is 8 cm. Pour the water into another cuboid glass jar, which is 16 cm long and 10 cm wide The height is 5cm. How high is the poured water? There are three oil drums of a, B and C. the volume of B is 12 cubic decimeters larger than that of A. the volume of C is 13 cubic decimeters larger than that of B. the volume of C is twice that of A. what are the volumes of the three oil drums of a, B and C?

Fill a square glass jar with water whose edge length is 8 cm. Pour the water into another cuboid glass jar, which is 16 cm long and 10 cm wide The height is 5cm. How high is the poured water? There are three oil drums of a, B and C. the volume of B is 12 cubic decimeters larger than that of A. the volume of C is 13 cubic decimeters larger than that of B. the volume of C is twice that of A. what are the volumes of the three oil drums of a, B and C?

1. Water volume = 8 × 8 × 8
Water tank height = 8 × 8 × 8 / (16 × 10) = 3.2 cm
2. B is 12 cubic decimeters bigger than a, C is 13 cubic decimeters bigger than B
C is 12 + 13 = 25 cubic decimeters larger than a
So the volume of a is 25 cubic decimeters
C Volume 25 × 2 = 50 cubic decimeter
The volume of B is 25 + 12 = 37 cubic decimeter

Make a cuboid glass jar without cover, 8 decimeters long, 6 decimeters wide, how many square decimeters of glass do you need
Prawn, do me a favor. I need a real one

6*8+5*8*2+5*6*2=188

It is known that there is a point B (1, n) on the straight line y = MX-1, and its distance from the origin is 10, then the area of the triangle formed by the straight line and the two coordinate axes is ()
A. 12b. 14 or 12C. 14 or 18D. 18 or 12

The distance from B (1, n) to the origin is 10, N2 + 1 = 10, i.e. n = ± 3. Then B (1, ± 3) is substituted into the analytic formula of a function to obtain y = 4x-1 or y = - 2x-1. (1) the area of the triangle formed by y = 4x-1 and two coordinate axes is 12 × 14 × 1 = 18; (2) the area of the triangle formed by y = - 2x-1 and two coordinate axes is 12 × 12 × 1 = 14

Factoring 9-x2 + 13x2 + 36

The first floor is not broken down at all
12*x^2+45
Cannot decompose in integer range
It cannot be decomposed in the range of rational numbers
It cannot be decomposed in the range of real numbers
In the plural
[(2 radical 3) x + (3 radical 5) I] [(2 radical 3) x - (3 radical 5) I]

It is proved that if K is a prime, then for any positive integer n, K is divisible by the K power of n minus n

If (n, K)! = 1, because K is a prime, then n is a multiple of K, and n ^ k - n is obviously a multiple of K. if (n, K) = 1 according to Euler's theorem, then. N ^ φ (k) ≡ 1 (MOD K) and for the prime K, φ (k) = k-1, so n ^ (k-1) divided by K remainder is 1, that is, n ^ (k-1) - 1 is a multiple of K, then n ^ k - n = n (n ^ k-1), is K

P is the point on the ellipse x ^ 2 / 25 + y ^ 2 / 16 = 1, and the left and right focus is F1, F2. If the midpoint of Pf1 is m, we prove Mo = 5-1 / 2pf1

Please draw a graph. M is the midpoint of f1p. 0 is the midpoint of F1F2. OM is the median line of ⊿ f1f2p,
∴OM＝（1/2）F2P.F1M＝（1/2）F1P.
OM+MF1＝（1/2）（F1P＋F2P＝10/2＝5
That is: om = 5-mf1 = 5 - (1 / 2) f1p

26 is the product of two prime numbers () and ()

26 is even. According to the parity of the product, only odd × even = even
There is only one even number 2 in the prime number, so the other prime number is 26 △ 2 = 13
26 is the product of two prime numbers (2) and (13)

Given function f (x) = loga (8-ax)
1) If f (x)
It's because the formula on the left is a decreasing function

No
Because when a > 1, a has innumerable values
So 9 / A-A and 8 / a have countless values
So it can't be changed into numbers

Prove that the log of a is based on a, and the logarithm of n = n (a > 0, and a is not equal to 1)
Prove that the log of a is based on a, the logarithm of n = n, that is [a ^ (log an) = n] (a > 0, and a is not equal to 1)
I've done it several times, but it's different,

.
This is the most basic theorem of logarithm!
Let n = a ^ k, then k = log a n
So a ^ k = n = a ^ (log a n)

Given that X: Y: z = 3:4:7, and 2x-y + Z = - 18, find the formula x + 2y-z

x：y：z=3：4：7
x=3a,y=4a,z=7a
2x-y+z=-18
6a-4a+7a=-18
a=-2
x+2y-z
=3a+8a-7a=4a=-8