A cuboid with a length of 8 cm, a width of 5 cm and a height of 3 cm and a cube iron block with an edge length of 6 cm are melted and cast into a cylinder with a height of 10 cm to find a circle What is the area of the bottom of the column?

8*5*3+6*6*6/10

A rectangular iron block 7 cm in length, 6 cm in width and 4.5 cm in height and a cube iron block 5 cm in edge length are fused and cast into a large cylinder. The bottom area of the cylinder is 78.5 square cm. What is the height of the cylinder?

(7 × 6 × 4.5 + 5 × 5 × 5) △ 78.5, = 314 △ 78.5, = 4 (CM); answer: the height of the cylinder should be 4cm

A rectangular iron block of 9cm in length, 7cm in width and 3cm in height and a cube iron block of 5cm in edge length were fused into a cylinder
The ground diameter of this cylinder is 20cm. How high is it?!

Hello, jimmhe225
The cuboid of 9cm, 7cm and 3cm in length, width and height is 9x7x3 = 189 cubic cm
The volume of a cube with an edge length of 5cm: 5x5 = 125cm3
Total volume: 189 + 125 = 314cm
The diameter is 20cm and the radius is 20 △ 2 = 10cm
Bottom area: π × 10 ^ 2 = 314 square centimeter
Height = volume ／ bottom area = 314 ／ 314 = 1cm
I wish you progress in your study!

A math problem: cut a 4 / 3 (three fourths) meter rope into 6 sections, each section is () meters long, and how many parts of a meter is each section?

Cut 4 / 3 (three fourths) meters of rope into 6 sections, each section is (8 / 1) meters long, and each section is 1 / 8 of 1 meter
Do not understand can ask, help please adopt, thank you!

f(x)=x(x-1)(x+2)(x-3)(x+4)…… (x + 100), find f '(1)

F '(x) = [x' (x-1) (x + 2) (x-3) (x + 4); (x + 100)] + [x (x-1) '(x + 2) (x-3) (x + 4); (x + 100)] +... + [x (x-1) (x + 2) (x-3) (x + 4); (x + 100)'] except for the second term, all other terms contain the factor (x-1). When x = 1, these terms are 0, so f '(1) = x (x-1)' (x + 2) (x-3) (x + 4); (x + 100)

The solution of equation () x = 15 is 6

9+x=15

Simplify tan10 ° + radical 3tan10 ° tan50 ° + tan50 °

=Tan60 (1-tan10tan50) + root 3tan10 ° tan50 °
=Root 3

The train accelerates on the straight track with the acceleration of 1m / S2. A passenger in the carriage reaches out of the window and releases an object from 2.5m above the ground. If the air resistance is not considered, the horizontal distance between the object and the passenger is (g = 10m / S2) ()
A. 0b. 0.50mc. 0.25md

Let v be the speed of the train when the ball is released. According to h = 12gt2, the time of horizontal throwing motion of the object is t = 2hg = 2 × 2.510s = 22s, the horizontal displacement of the object is X1 = VT, and the displacement of the train is x2 = VT + 12at2. Then the displacement difference is △ x = x2 − X1 = 12at2 = 12 × 1 × 12m = 0.25m

For a project, team a can complete it in 10 days and a pair can complete it in 15 days. (1) if team a and team B can complete it in X days, the equation is
(2) If team a does it for three days, and team B supports it, and team B completes three fourths of the task after y days, then the equation is?

（1）
X/10+X/15=1
X/6=1
X=6
It can be finished in 6 days
(2)
3/10+Y/10+Y/15=3/4
Y/6=9/20
Y=1.8
B did it for 1.8 days

A cuboid with a length of 8 cm, a width of 5 cm and a height of 3 cm and a cube iron block with an edge length of 6 cm are melted and cast into a cylinder with a height of 10 cm to find a circle What is the area of the bottom of the column?