A cuboid container is 6 cm long and 4.5 cm wide. The water surface is 1 cm away from the opening of the container. Put two eggs of the same size and overflow some water. Then take out the two eggs and the water surface drops 2 cm. Calculate the volume of each egg

A cuboid container is 6 cm long and 4.5 cm wide. The water surface is 1 cm away from the opening of the container. Put two eggs of the same size and overflow some water. Then take out the two eggs and the water surface drops 2 cm. Calculate the volume of each egg

Overflow part of the water, then static, indicating full
Take out two eggs again, water surface drops 2 cm again, the water that shows to drop 2 cm is the volume of egg
So, V egg = 6 times 4.5 times 2 / 2 = 27 cubic centimeters

A cuboid wood block is 8 cm long, cut into two cuboids along the height, and the surface area increases by 4 square decimeters. What is the volume of the original cuboid

Bottom area multiplied by height equals volume
That is to say, 8 * 4 = 32 (cubic decimeter)
*=By

A natural number is either prime or composite, or even or odd. Right or wrong?

The whole sentence is wrong
It is wrong to say separately: "a natural number is either prime or composite", because there is only one exception, 1 - it is neither prime nor composite
If we say, "a natural number is either even or odd," it is correct because 1 is odd
Supplement: whether 0 is a natural number or not remains controversial

Given that the intersection of the lines Y1 = k1x-1 and y2 = k2x + 2 is on the X axis, then K1: K2=

The intersection of Y1 = k1x-1 and y2 = k2x + 2 is on the x-axis
∴0=k1x-1
0=k2x+2
∴x=1/k1=-2/k2
∴k1:k2=-1:2

Change the following sentences into plural
1.That red car is my sister's.
____ red____ ____ ____ siter's.
2.Who is that woman?
Who____ ____ ____ ?
3.This is a pencil-box.
____ ____ ____ .
4.He is an English child.
____ ____ ____ ____ .
5.There is a bus on the stop.
There____ there____ on the bus stop.
6.Is this your bike Yes,it is.
____ ____ your____ ?Yes,____ are

1.That red car is my sister's.
__ These__ red_ cars___ _ are___ _ our___ siter's.
2.Who is that woman?
Who__ are _ those__ _ women___ ?
3.This is a pencil-box.
__ These__ _ are_ _ pencil-boxes___ .
4.He is an English child.
_ They___ __ are__ _ English___ _ children___ .
5.There is a bus on the stop.
There__ are__ there___ buses_ on the bus stop.
6.Is this your bike Yes,it is.
__ Are__ __ these__ your_ bikes___ ?Yes,__ they__ are

Finding the vertex coordinates of parabola y = - 2 / 3x-4x + 12
3x is squared

y=-2/3(x²+6x)+12
=-2/3(x²+6x+9-9)+12
=-2/3(x²+6x+9)+2/3×9+12
=-2/3(x+3)²+18
=-2/3[x-(-3)]²+18
Vertex (- 3,18)

If the two equal angles are obtuse angles, are the two triangles congruent?

There are two cases: one is congruent; the other is an isosceles triangle whose difference is equal. The equal angle is the base angle of isosceles triangle. Because the base angle of isosceles triangle must be acute angle. So if the equal angle is obtuse angle, it must be congruent
Please accept

It is known that f (x) = (x ^ 2 + ax + 2) e ^ X. if f (x) is monotone on R, the value range of a is obtained
Function problem

The derivative f '(x) = (2x + a) e ^ x + (x ^ 2 + ax + 2) e ^ x, which is greater than zero, is divided by e ^ x at both ends
x^2+(a+2)x+a+2>0
The coefficient of quadratic term is greater than zero, so the equation x ^ 2 + (a + 2) x + A + 2 = 0 has no solution or multiple roots
△=(a+2)^2-4(a+2)

Give me 50 exercises of factorization in grade two of junior high school

As shown in the figure, one intersection of the image of quadratic function y = - x2 + 2x + m and X axis is a (3, 0), the other intersection is B, and it intersects with y axis at point C. (1) find the value of M; (2) find the coordinates of point B; (3) there is a point d (x, y) (where x > 0, Y > 0) on the image of quadratic function, so that s △ abd = s △ ABC, find the coordinates of point D. [vertex coordinates of parabola: (- B2A, 4ac − b24a)]

(1) ∵ the intersection of the image of quadratic function y = - x2 + 2x + m and X axis is a (3,0), ∵ 9 + 2 × 3 + M = 0, and the solution is m = 3; (2) ∵ the analytic expression of quadratic function is y = - x2 + 2x + 3, ∵ when y = 0, - x2 + 2x + 3 = 0, and the solution is x = 3 or x = - 1, ∵ B (- 1,0); (3) as shown in the figure, connect BD, ad, and cross point d to make de ⊥ AB, ∵ when x = 0, y = 3, ∵ C (0,3), if s △ abd = s △ ABC If ∵ D (x, y) (where x ﹥ 0, y ﹥ 0), then OC = de = 3, ∵ when y = 3, - x2 + 2x + 3 = 3, the solution is: x = 0 or x = 2, ∵ the coordinates of point D are (2, 3). Another method: point D and point C are symmetric about x = 1, so D (2, 3)