Choose the right pronunciation for the Braille The first month Gong Gong Five elements Neck (J ǐ ng J ì ng (fourth tone)) Fu fo Kitchen room Fu fo Change it As if (Fu fo)

Choose the right pronunciation for the Braille The first month Gong Gong Five elements Neck (J ǐ ng J ì ng (fourth tone)) Fu fo Kitchen room Fu fo Change it As if (Fu fo)


First month
Offering (Gong Si Sheng) products
Five elements
Neck (J ǐ ng) if it's northern, it should be "neck g ě ng"
Buddha (FO)
Kitchen



Examples of selecting pronunciation with Braille in Grade Four
Come on!


Choose the correct pronunciation for the underlined words and use "√"
The first month (zh ē ng zh è ng) flies (B ē n B è n)
Sowing (s ǎ s ā) giving (J ǐ g ě I)
[train of thought] to master polysyllabic words accurately, we must first understand several pronunciations of polysyllabic words, then be familiar with the usage and meaning of each pronunciation, and then choose according to the specific words
Answer: Zhang ng B ē n s ǎ J ǐ
Is that ok



Known arithmetic sequence {an}, a3a7 = - 16, A4 + A6 = 0, find {an} before N and Sn!


a3a7=(a1+2d)(a1+6d)=a1^2+8a1d+12d^2=-16
a4+a6=a1+3d+a1+5d=2a1+8d=0 a1=-4d
arcsinx-x
(-4d)^2+8*(-4d)d+12d^2=-16
D = 2 or D = - 2
A1 = - 8 or A1 = 8
Sn=na1+n(n-1)d/2
Sn = n ^ 2-9n or Sn = - n ^ 2 + 9N



The time taken for a particle to make a uniformly accelerated linear motion line from a to B and from B to C is 2S, and the displacements of the first 2S and the second 2S are 8m and 12m respectively. The acceleration, initial velocity and final velocity of the particle motion are calculated
In the process of training handover, it is found that: a can keep the speed of 9m / s to complete the whole race after a short distance acceleration; B can accelerate evenly from the start to the start. In order to determine the time of B's start, it is necessary to set a mark at an appropriate position in front of the relay area, When B hears the command at the front end of the relay area, he starts and is overtaken by a at the same speed as a to complete the handover. It is known that the length of the relay area is L = 20m
(1) In this exercise, the acceleration of B is a
(2) The distance between B and the end of the relay zone at the completion of taking over


1. It is relatively time-consuming and laborious to solve this kind of problems with equations
I'll teach you a way
In the motion of uniform speed change:
The displacement difference in continuous equal time intervals (T) is a constant (at & # 178;)
Explain:
For example: the first second, the second second, the third second
These are continuous, equal time intervals (all 1 second, i.e. t = 1s)
The displacement in the second second second is different from that in the first second by a t-178;
That is: X (2) - x (1) = at & # 178;
The difference between the displacement in the third second and that in the second second is a T & # 178;
That is: X (3) - x (2) = at & # 178;
Push it down
That is: the difference between the displacement in the next T and that in the previous t is constant (at & # 178;)
In the problem, let the acceleration be a, the initial velocity be VO, and the final velocity be v
The displacement in the previous t (2S) is ab = X1 = 8m;
Displacement BC = x2 = 12m in the latter t (2S)
Then: X2 - X1 = at & # 178;
That is: 12 - 8 = a · 2 & # 178;
A = 1m / s and 178;
Point B is the intermediate point from a to C
According to the instantaneous speed in the middle = average speed
B point velocity VB = vplane = AC / 4S = (8 + 12) / 4 = 5ms
Then:
Initial velocity VO = VA = VB - at = 5 - 1x2 = 3m / S
Final velocity v = VC = VB + at = 5 + 1x2 = 7m / S
Continue to write the second question for you
I'm dizzy! You missed the number in the title, but it's hurting me! (thought it was m point)
I searched it. The original question is like this:
"A marked x = 13.5m in front of the relay area"
2. From the meaning of the title, we can know:
① The distance from the starting position of a to the position of B (the front end of the relay area) d = 13.5m
② When finishing the baton handover, the distance (x B) B has run is less than 20M (it has not run to the end of the relay zone)
③ From point m, a moves at a constant speed v a = 9 m / s, B's initial velocity VO = 0, and final velocity v = 9 m / s
④ From point m, x a = x B + D
(1) In this exercise, B's acceleration a before taking the stick
Let the time of this process be t
The initial velocity VO of B = 0, the final velocity v = 9m / s
Average velocity of B = (initial velocity + final velocity) / 2 = (0 + 9) / 2 = 4.5m/s
Then: x B = 4.5t
X a = v a T = 9t
That is: x a = 2x B, and x B = D = 13.5m
Let me show you:
"X a = 2x B" brings in "x a = x B + D"
2X B = x B + D
X B = D
So: x a = 2x B = 2D = 2x13.5 = 27m
Then the time t = x A / V A = 27 / 9 = 3S
Then the acceleration of B a = (v-vo) / T = (9-0) / 3 = 3m / S & # 178;
(2) The distance between B and the end of the relay zone at the completion of taking over
It has been known that:
The displacement of B is x B = D = 13.5m
Relay zone length L = 20m
Then, the distance between B and the end of relay zone at the time of taking over is L - x B = 20 - 13.5 = 6.5m



Dad takes a day off every 6 days, mom takes a day off every 7 days. They take a day off on March 4 at the same time. When is the next time they take a day off


6,7 least common multiple: 42
March 4 + 42 days = April 15



A mathematical problem of equation
For a three digit number, the number on the tenth digit is 3 times smaller than that on the hundredth digit, and the number on the single digit is 1 times larger than that of the book on the hundredth digit. If you exchange the number on the tenth digit of the three digit number with the number on the hundredth digit to get a new number, the original three digit number will be 270 smaller, and the original three digit number will be calculated


Let X be the number on the hundreds, then the number on the tens is 4x-3, the number on the individual bits is 3x + 1, the original number is 100x + 10 (4x-3) + (3x + 1), the new number is 100 (4x-3) + 10x + (3x + 1) - 100x-1



If the product of equation 3x & # 178; + X + k = 0 is - 3, then the value of K is


-9. According to Weida's theorem, two products are equal to K / 3, so k = - 9



Please tell me a math problem, what is called substitution elimination method


The main steps of changing "two variables" into "one variable" are: to express an unknown number in one equation with an algebraic formula containing another unknown number, and substitute it into another equation, so as to eliminate an unknown number and change the system of quadratic equations of two variables into linear equations of one variable. This method of solving the system of equations is called substitution elimination method, which is abbreviated as substitution method



The sequence {an} is an arithmetic sequence with non-zero tolerance, and A5, a8 and A13 are three adjacent terms of the arithmetic sequence {BN}. If B2 = 5, then BN = ()
A. 5•(53)n−1B. 5•(35)n−1C. 3•(35)n−1D. 3•(53)n−1


∵ {an} is an arithmetic sequence with non-zero tolerance, and A5, A8, A13 are the adjacent three terms of the arithmetic sequence {BN}, ∵ (A5 + 3D) 2 = A5 (A5 + 8D), ∵ A5 = 92d, ∵ q = A5 + 3da5 = 152d92d = 53, ∵ B2 = 5, q = 53, ∵ B1 = b2q = 3, ∵ BN = b1qn − 1 = 3 · (53) n − 1



67400 cm3 = () DM2


67400 cm3 = (67.4) DM3